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asambeis [7]
3 years ago
8

1 point There are 118 known elements. How many elements have atoms, in their ground-state, with core electrons whose quantum num

bers are n
Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

The question is incomplete; the complete question is;

There are 118 known elements. How many elements have atoms, in their ground state, with core electrons whose quantum numbers are n=3 and l=1?

a. 10

b. 6

c. 100

d. 18

Answer:

c. 100

Explanation:

If we look closely at the periodic table, we will notice that there 100 elements that occur after argon whose electronic configuration is; 1s2 2s2 2p6 3s2 3p6.

This means that there every other element after argon must have a 3p sublevel as part of its core electrons. In the 3p sublevel, n=3 and l=1.

If we diligently count the number of elements from potassium (immediately after argon) to Oganesson (element 118) we have a total of 100 elements all having core electrons of quantum numbers are n=3 and l=1.

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7 0
3 years ago
Determine the mmol of both starting materials (factoring in that formic acid is not pure, but rather 88% weight/volume, or 88g/1
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Solution :

Molecular      Molar Mass       Volume      Density       Mass      Moles      nmoles

formula            (g/mol)               (mL)          (g/mL)           (g)

$C_6H_8N_2$            108.14                                                    0.108      0.001          1

HCOOH           46.02                0.064          1.22     0.07808     0.0017       1.7

mmoles of o-phenylenediamine = 1 mmoles

mmoles of formic acid = 1.7 \approx 2 mmoles

From the reaction of o-phenylenediamine and formic acid, we see,

1 mmole of o-phenylenediamine reacts with 1 mmole of formic acid.

But here, 2 mmoles of the formic acid , this means that the formic acid is an excess reagent and the o-phenylenediamine is the limiting reagent here.

The amount of product depends on the limiting reagent that is o-phenylenediamine. So, 1mmole of o-phenylenediamine will give 1mmole of product.

molar mass of Benzimidazole = 118.14 g/mol

mmoles of Benzimidazole formed = 1 mmol

Mass of benzimidazole formed = molar mass x \frac{nmoles}{1000}

                                                    $=\frac{118.14 \times 1}{1000}$

                                                     = 0.11814 g

So the theoretical yield of Benzimidazole is = 0.118 g = 118mg

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Explanation:

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