Answer:
<em>1</em><em>)</em><em> </em><em>P</em><em>late</em><em> </em><em>tectonic</em><em> </em><em>theory</em>
<em>2</em><em>)</em><em> </em><em>Lithospheric</em>
<em>3</em><em>)</em><em> </em><em>Plates</em>
<em>4</em><em>)</em><em> </em><em>Heat</em>
<em>5</em><em>)</em><em> </em><em>Less</em><em> </em><em>dense</em>
<em>6</em><em>)</em><em> </em><em>Conventional current</em>
<em>7</em><em>)</em><em> </em><em>Magma</em>
<em>8</em><em>)</em><em> </em><em>Ocean</em><em> </em><em>crust</em>
<em>9</em><em>)</em><em> </em><em>Slowly</em>
<em>10</em><em>)</em><em> </em><em>Drifting</em><em> </em><em>away</em><em> </em>
Answer:
The distance is 3.1 m
Explanation:
The position vector of the fly relative to the corner of the wall is
r = (3.1, 0.5).
The distance of the fly from the corner will be calculated as the magnitude of the vector "r"
magnitude of vector 
Since the numbers to be added have only one decimal place 3.<u>1</u> and 0.<u>5</u>, the result of the sum will have to have one decimal place. The result of the square root will also have one decimal place.
Answer:
60.18 N
Explanation:
Given that:
The force applied on the sled = 100 N
Suppose, the angle between the sled rope and the ground = 53°
The horizontal force which acts in the horizontal direction can be expressed as:



But if the angle between the sled rope is parallel to the ground. Then, we use an angle on a straight line which is = 180°


= 100 × -1
= -100 N
Well, if the bag is moving across the floor at a constant velocity. Then I would assume that the Fnet force is equal to 0, and thus the value of acceleration would also be equal to 0.