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Alchen [17]
3 years ago
10

Suppose astronomers discover a type-M star with a very large luminosity. What type of star is it likely to be

Physics
1 answer:
lianna [129]3 years ago
8 0

Answer: A red supergiant

Explanation:

Red supergiants are the stars that have a supergiant luminosity which has a class of either K or M spectral type. In terms of volume, they are regarded as the largest stars on Earth even though they are not the most luminous.

Red supergiants are formed when a star collapses after the hydrogen fuel that the star has in its core runs out and

then fusion begins when the outer shells of hydrogen gets hot.

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Starting from rest, a dragster travels a straight 1/4 mi racetrack in 6.70 s with constant acceleration. What is its velocity wh
Airida [17]
<h2>Its velocity when it crosses the finish line is 119.40 m/s</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = ?

        Time, t = 6.70 s      

        Displacement, s = 1/4 mi = 0.25 mi = 400 m

     Substituting

                      s = ut + 0.5 at²

                      400 = 0 x 6.70 + 0.5 x a x 6.70²

                      a = 17.82 m/s²

     Now we have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = ?

     Time, t = 6.7 s

     Acceleration, a = 17.82 m/s²

     Substituting

                      v = u + at  

                      v = 0 + 17.82 x 6.7

                      v = 119.40 m/s

Its velocity when it crosses the finish line is 119.40 m/s

6 0
4 years ago
A circuit has resistors R 1 = 468 Ω and R 2 = 125 Ω R1=468 Ω and R2=125 Ω , and two batteries V 1 = 12.0 V and V 2 = 3.00 V V1=1
Greeley [361]

Answer:

0.0192A

Explanation:

Since, the reading of the galvanometer is 0 A, the voltage across the resistance R will be:

Step 1

VR = V2

VR = 3.00v

Step 2

Calculating the current through the resistance R as below,

IR = V1 - V2 /R1

IR = 12 - 3 /468

IR =0.0192A

7 0
4 years ago
Suppose you increase the height of the object without changing its depth under water. What will happen to the force due to press
Natali [406]

Answer:Remains same

Explanation:

Given

It is given that the depth is constant and we are only increasing the  height of object submerged in the water

thus Force due to Pressure remains same as this force depends upon the depth of object with respect to free surface of Fluid.

Pressure at a depth h with density \rhoof fluid is given by

P=\rho \times g\times h

and Force=Pressure \times area

8 0
4 years ago
Consider a block sliding down a ramp whose motion is opposed by frictional forces. The total energy of this system is modeled by
Irina18 [472]

Answer:

Energy Flows Quick check answers:

1. Ffd.

2. The kinetic energy decreases, and gravitational potential energy increases.

3. The internal energy of the system increases.

4. KEbox= Etotal-mgh

5. Etotal = 1/2m1(v1)^2+1/2m^2(v2)^2+U

8 0
3 years ago
Read 2 more answers
At a constant temperature, the volume of a gas doubles when the pressure is reduced to half of its original value. This is a sta
djyliett [7]

Answer: Boyle’s law

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

As pressure is decreased to half, the volume is increased to doubled.

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T     (At constant pressure and number of moles)

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

Combined gas Law: combining the three laws:

PV\propto T  

6 0
4 years ago
Read 2 more answers
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