Hence molar mass (M) of Magnesium Chloride; MgCl.= M (2Cl)+M (Mg) = 70.90+24.31=95.21 g/mol.
Since the pressure is constant, you can use the equation V₁/T₁=V₂/T₂ and solve for T₂. (T₂=(T₁/V₁)V₂)
since this is a gas law type question, the temperatures need to be in kelvin therefore you need to convert 15°C to kelvin. 15°C+273=288K. The volume are already in L so they don't have to be converted.
now you just need to plug everything in:
T₂=(288K/99L)x1200L
T₂=3491K
The answer is you need if you have a 99L of gas at 288K, you have to increase the temperature to 3491K to get a volume of 1200L if the pressure remains constant.
I hope this helps. Let me know in the comments if anything is unclear.
Answer:
Option C. 0.23 molar
Explanation:
The following data were obtained from the question given:
C1 = 0.5 M
V1 = 340mL
V2 = since 400mL was added to the original volume, therefore = 340 + 400 = 740mL
C2 =?
The concentration of the diluted solution can be calculated by using the following:
C1V1 = C2V2
0.5 x 340 = C2 x 740
Divide both side by 740
C2 = (0.5 x 340) / 740
C2 = 0.23M
Therefore, the new concentration of the solution is 0.23M
