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4 years ago

which statement describes the magnetic force on a charged particle when the particle is moving at a right angle to the field

Physics

2 answers:

Shtirlitz [24]4 years ago

6 0

Answer:

It is the strongest force possible.

Explanation:

elena-s [515]4 years ago

3 0

A. It is the strongest force possible.

Explanation:

The force exerted on a charged particle moving in a region with a magnetic field is given by the following equation:

$F=qvB sin \theta$

where

q is the magnitude of the charge

v is the velocity of the particle

B is the strength of the magnetic field

$\theta$ is the angle between the direction of the velocity and of the field

From the equation, we notice that:

The force is maximum when the particle is moving perpendicular to the magnetic field, therefore when $\theta=90^{\circ}$ and $sin \theta=1$
The force is zero when the particle is moving parallel (or anti-parallel) to the magnetic field, therefore when $\theta=0$ and $sin \theta = 0$

Based on these observation, we can immediately conclude that the only correct option among the given choices is

A. It is the strongest force possible.

Learn more about magnetic fields:

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gavmur [86]

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8 0

4 years ago

A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the

Novay_Z [31]

Answer:

It will be cut in half

Explanation:

The diffraction of a slit is given by the formula

a sin θ = m where

a = width of the slit,

λ = wavelength and

m = integer that determines the order of diffraction.

Next we divide both sides by a, we have

sin θ = m λ / a

Also, recall that

a’ = 2 a

Then we substitute in the previous equation

2asin θ' = m λ, if divide by 2a, we have

sin θ' = (m λ / 2a).

Now again, from the first equation, we said that sin θ = m λ / a, so we substitute

sin θ ’= sin θ / 2

Then we use trigonometry to find the width, we say

tan θ = y / L

Since the angle is small, we then have

tan θ = sin θ / cos θ

tan θ = sin θ, this then means that

sin θ = y / L

we will then substitute

y’ / L = y/L 1/2

y' = y / 2

this means that when the slit width is doubled the pattern width will then be halved

4 0

4 years ago

Someone help im boredd

Oduvanchick [21]

Answer:

ok what is the question you need help with

Explanation:

6 0

3 years ago

Read 2 more answers

A square coil ℓ = 2cm on a side with 30 turns rotates in a uniform magnetic field, B~ = B0zˆ = 0.1Tˆz, such that the normal of t

kow [346]

Answer:

a) 1.2*10^{-3}cos(1.25t)

b) 0.49mV

Explanation:

a) The coil rotates periodically with period T. Hence, we can write the variation of the magnetic flux with a sinusoidal function, and with max flux NAB. Thus, we have that:

$\Phi_B(t)=NABcos(\omega t)\\\\\omega=\frac{2\pi}{T}=1.25\frac{rad}{s}\\\\A=l^2=(0.02m)^2=4*10^{-4}m^2\\\\B=0.1T\\\\\Phi_B(t)=1.2*10^{-3}cos(1.25 t) W$

where we have used the values given by the information of the problem for N B and A.

the emf is given by:

$emf=-\frac{d\Phi_B}{dt}=-NBA\omega sin(\omega t)\\\\emf(t=12.5s)=-(30)(0.1T)(4*10^{-4})(1.25\frac{rad}{s})sin(1.25*12.5)=1.49*10^{-4}V=0.49mV$

hope this helps!!

5 0

3 years ago

HELP PLS

melisa1 [442]

Answer:

red I think

Explanation:

it's on red so I googled some of it and the closest was red

4 0

3 years ago