A cannon is shot from the ground with a speed of 100 m/s at an unknown angle, if it
1 answer:
Answer:
The angle of the launch is 17.09 degrees.
Explanation:
Given that,
The initial speed of a cannon is 100 m/s
It is launched at some angle and it lands after being in the air for 6 s.
We need to find the angle of the launch.
The time taken by the projectile to reach the ground is called the time of flight. It is given by the formula as follows :
Here, = launch angle
Hence, the angle of the launch is 17.09 degrees.
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Answer:
t = 1.4[s]
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 50 [kg]
v = velocity [m/s]
F = force = 200[N]
t = time = [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
where:
m₁ = mass of the object = 50 [kg]
v₁ = velocity of the object before the impulse = 18.2 [m/s]
v₂ = velocity of the object after the impulse = 12.6 [m/s]