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3 years ago

A cannon is shot from the ground with a speed of 100 m/s at an unknown angle, if it

Physics

1 answer:

hodyreva [135]3 years ago

7 0

Answer:

The angle of the launch is 17.09 degrees.

Explanation:

Given that,

The initial speed of a cannon is 100 m/s

It is launched at some angle and it lands after being in the air for 6 s.

We need to find the angle of the launch.

The time taken by the projectile to reach the ground is called the time of flight. It is given by the formula as follows :

$T=\dfrac{2u\sin\theta}{g}$

Here, $\theta$ = launch angle

$\sin\theta=\dfrac{Tg}{2u}\\\\\sin\theta=\dfrac{6\times 9.8}{2\times 100}\\\\\theta=\sin^{-1}(0.294)\\\\\theta=17.09^{\circ}$

Hence, the angle of the launch is 17.09 degrees.

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What were some major reasons for the american television from analog broadcast to digital broadcast?

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Answer: It frees up valuable portions of the broadcast spectrum, it has better audio and picture quality, and there are more options on digital broadcasting

Explanation:

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3 years ago

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astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating o

devlian [24]

Answer:

The right answer is:

(a) 63.83 kg

(b) 0.725 m/s

Explanation:

The given query seems to be incomplete. Below is the attachment of the full question is attached.

The given values are:

T = 3 sec

k = 280 N/m

(a)

The mass of the string will be:

⇒ $T=2 \pi\sqrt{\frac{m}{k} }$

or,

⇒ $m=\frac{k T^2}{4 \pi^2}$

On substituting the values, we get

⇒ $=\frac{280\times (3)^2}{4 \pi^2}$

⇒ $=\frac{280\times 9}{4\times (3.14)^2}$

⇒ $=68.83 \ kg$

(b)

The speed of the string will be:

⇒ $\frac{1}{2}k(0.4)^2=\frac{1}{2}k(0.2)^2+\frac{1}{2}mv^2$

then,

⇒ $v=\sqrt{\frac{k((0.4)^2-(0.2)^2)}{m} }$

On substituting the values, we get

⇒ $=\sqrt{\frac{280\times ((0.4)^2-(0.2)^2)}{63.83} }$

⇒ $=\sqrt{\frac{280(0.16-0.04)}{63.83} }$

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3 years ago

What organs make up the skeletal system

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3 years ago

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melisa1 [442]

Answer:

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Explanation:

hope it helps ya

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2 years ago

The potential difference between the surface of a 3.0-cm-diameter power line and a point 1.0 m distant is 3.9 kV. Find the line

Korolek [52]

Answer:

The linear charge density is 5.19 X 10⁻⁶ C/m

Explanation:

The potential difference between two cylinders, is given as

V = (λ/2πε)ln(b/a)

where;

λ is the line charge density on the power line.

b is the distance between the power line = 1 m

a is the radius of the wire = 1.5 cm = 0.015 m

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V*2πε = λ* ln(b/a)

3900 *(2π*8.9 x10⁻¹²)= λ *ln(1/0.015)

2.1812 X 10⁻⁷ = 4.1997* λ

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Therefore, the linear charge density is 5.19 X 10⁻⁶ C/m

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3 years ago