Answer:
C. Athletic performance peaks during teen years
Explanation:
According to me this is the right answer because in A it is actually men’s athletic ability that peeks later than women. In B, it is kinda obvious that is not true.
Hope this helps!
Answer:
D. 2.5 V
Explanation:
Electric potential of a point in space is a scalar magnitude that allows a measurement of the electric field at that point to be obtained through the electrostatic potential energy that a electric charge would acquire if it is placed at that point.
Answer:
The correct option is;
The index of refraction of the second medium is lower
Explanation:
The index of refraction of a material indicates the magnitude of the optical density of a material. The index of refraction or the refractive index, n, are indices (ratio) of the speed of light through an optically dense medium relative to the speed of light through a vacuum.
The definition of the refractive index is the number of times light travelling through a medium would be slower than light travelling through vacuum
Therefore, the index of refraction of a second medium that is less optically dense than a first medium from which light originates and travels through it would be lower than the index of refraction of the first medium
I think the airplan flies in same speed 400
The complete question is missing, so i have attached the complete question.
Answer:
A) FBD is attached.
B) The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Explanation:
A) I've attached the image of the free body diagram.
B) The formula for the net force is given as;
F_net = mv²/r
We know that angular velocity;ω = v/r
Thus;
F_net = mω²r
Now, the minimum downward force is the weight and so;
mg = m(ω_min)²r
m will cancel out to give;
g = (ω_min)²r
(ω_min)² = g/r
ω_min = √(g/r)
The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
