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Liula [17]
2 years ago
14

This is a two part question:

Physics
1 answer:
adelina 88 [10]2 years ago
8 0

Answer:

1. 310 N

2. 310 N

Explanation:

1. Determination of the net force.

Force applied (Fₐ) = 430 N

Force experience (Fₑ) = 120 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fₑ

Fₙ = 430 – 120

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N

2. Determination of the net force.

Force applied (Fₐ) = 375 N

Force of friction (Fբ) = 65 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fբ

Fₙ = 375 – 65

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N.

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A baseball pitcher throws the ball towards the batter at 90 mph. His bat connects with the ball for a line drive, after which th
forsale [732]

Answer:

F=-18412.9N, where the minus indicates the direction is opposite to that of the throw.

Explanation:

a)

Since MKS stands for meter-kilogram-second and we know that:

1\ hour = 3600\ seconds

1\ mile = 1600\ meters

1000g = 1kg

We can write that:

\frac{1\ hour}{3600\ seconds}=1

\frac{1600\ meters}{1\ mile}=1

\frac{1kg}{1000g}=1

These are conversion factors, equal to 1, so multiplying our results by them won't change their value, only their units.

So we have that:

90 mph=90 \frac{miles}{hour}(\frac{1\ hour}{3600\ seconds})(\frac{1600\ meters}{1\ mile})=40m/s

110 mph=110 \frac{miles}{hour}(\frac{1\ hour}{3600\ seconds})(\frac{1600\ meters}{1\ mile})=48.89m/s

145 g=145 g(\frac{1kg}{1000g})=0.145kg

b)

Newton's 2nd Law tells us that F=ma, and the definition of acceleration is a=\frac{\Delta v}{\Delta t}, so we have:

F=m\frac{\Delta v}{\Delta t}=m\frac{v_f-v_i}{t}

Taking the throw direction as the positive one, for our values we have:

F=m\frac{v_f-v_i}{t}=(0.145kg)\frac{(-48.89m/s)-(+40m/s)}{0.0007s}=-18412.9N

4 0
3 years ago
The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, wh
Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

v^2=v^2_o-2ax

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}

Next, consider that the formula for the force is:

F=ma

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

F=(820kg)(0.66\frac{m}{s^2})=542.20N

Hence, the required force to stop the car is 542.20N

4 0
1 year ago
A force of 16 N is applied to a 2 kg mass over 4 m. The surface is horizontal and frictionless. If the object is initially at re
KATRIN_1 [288]
C) Calculate the final speed.
6 0
2 years ago
What is the atomic number of hydrogen? A. 26 B. 14 C.35 D. 1
Elena L [17]

Answer:

D

Explanation:

The atomic number of hydrogen is 1, because hydrogen is considered the number #1 element in the periodic table. Hope this helps!

8 0
3 years ago
Read 2 more answers
If a bus has a mass of 1,021 kg, how much does the bus weigh?
lisov135 [29]
m=1 \ 021 \ kg \\ g=10 \ m/s^2 \\ \boxed{W-?} \\ \bold{Solving:} \\ \boxed{W=m \cdot g} \\ W=1 \ 021 \ kg \cdot 10 \ m/s^2 \\ \Rightarrow \boxed{W=10 \ 210 \ N}
6 0
3 years ago
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