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andre [41]
3 years ago
10

sodium is a highly reactive element which characteristic of sodium is most responsible for its reactivity

Chemistry
2 answers:
vlada-n [284]3 years ago
8 0

Answer:

The answer is B

Explanation:

AlexFokin [52]3 years ago
3 0
B) It's atomic mass is 22.990
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During an experiment,what is the factor you are testing called
Step2247 [10]

Answer:

the answer is variable

4 0
3 years ago
K2so4 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.450 m k2so4 solution.
amid [387]

<em>Answer:</em>

  • Conc. of K+ ions = 0.90 M
  • Coc. of SO4∧-2 = 0.45 M

<em>Explanation:</em>

<em>Data Given:</em>

Conc. of H2SO4 = 0.450

As sulphoric acid is a strong electrolyte, it completely dissociate into ions.

H2SO4 ⇆   2K+   +   SO4∧-2

.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.

                      K2SO4  :  K+                                          K2SO4  : SO4∧-2

                          1      =     2                                                   1     =    1

                     0.450   =   2× 0.450 = 0.90                     0.450 =  0.450×1 = 0.450

<em> Result:</em>

Conc. of potassium ion will be 0.90M    

Coc. of sulphate ions will be 0.45 M

8 0
3 years ago
Calculate the mass of NaCl needed to make 40% solution from 3kg of water ? Could you explain step by step please :-)
earnstyle [38]
Ok so 40 percent of 3000 grams which is 3 kg is 1200 grams 
So you would need 1.2kg or 1200 grams to make a 40% solution
3 0
3 years ago
4Fe +302 + 2Fe2O3 <br> How many grams of Fe2O3 will be produced from 10.0 g of Fe and 7.00 g of O2?
Molodets [167]

Answer:10g of Fe produces 14.37g of Fe2O3

7g of O2 produce 46.84g of Fe2O3

Explanation:

3 0
3 years ago
Determine the mass in grams of 4.69 x 1021 atoms of barium. (The
Virty [35]

Answer:

1.07 g Ba

Explanation:

Hello there!

In this case, according to the definition of the Avogadro's number and the molar mass, it is possible to say that 6.022x10^{23} atoms of barium equal one mole, and at the same time, 1 mole equals 137.327 grams of this element; thus, it is possible to say that 6.022x10^{23} atoms of barium have a mass of 137.327 grams; therefore, it i possible for us to calculate the required mass in grams as shown below:

4.69x10^{21}atoms*\frac{137.327gBa}{6.022x10^{23} atoms} \\\\=1.07gBa

Best regards!

5 0
3 years ago
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