<em>Answer:</em>
- Conc. of K+ ions = 0.90 M
- Coc. of SO4∧-2 = 0.45 M
<em>Explanation:</em>
<em>Data Given:</em>
Conc. of H2SO4 = 0.450
As sulphoric acid is a strong electrolyte, it completely dissociate into ions.
H2SO4 ⇆ 2K+ + SO4∧-2
.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.
K2SO4 : K+ K2SO4 : SO4∧-2
1 = 2 1 = 1
0.450 = 2× 0.450 = 0.90 0.450 = 0.450×1 = 0.450
<em> Result:</em>
Conc. of potassium ion will be 0.90M
Coc. of sulphate ions will be 0.45 M
Ok so 40 percent of 3000 grams which is 3 kg is 1200 grams
So you would need 1.2kg or 1200 grams to make a 40% solution
Answer:10g of Fe produces 14.37g of Fe2O3
7g of O2 produce 46.84g of Fe2O3
Explanation:
Answer:
1.07 g Ba
Explanation:
Hello there!
In this case, according to the definition of the Avogadro's number and the molar mass, it is possible to say that 6.022x10^{23} atoms of barium equal one mole, and at the same time, 1 mole equals 137.327 grams of this element; thus, it is possible to say that 6.022x10^{23} atoms of barium have a mass of 137.327 grams; therefore, it i possible for us to calculate the required mass in grams as shown below:

Best regards!