Hg(No3)2 +NaSO4 --->2NaNO3 + HgSO4(s)
calculate the moles of each reactant
moles=mass/molar mass
moles of Hg(NO3)2= 51.429g/ 324.6 g/mol(molar mass of Hg(NO3)2)=0.158 moles
moles Na2SO4 16.642g/142g/mol= 0.117 moles of Na2SO4
Na2SO4 is the limiting reagent in the equation and by use mole ratio Na2So4 to HgSO4 is 1:1 therefore the moles of HgSO4 =0.117 moles
mass of HgSO4=moles x molar mass of HgSo4= 0.117 g x 303.6g/mol= 35.5212 grams
Answer:
mass ratio of A/B is 2:1
Explanation:
Since the mass of box A = 10g
mass of box B = 5g
Mass of box C = mass of box A + mass of box
A ratio compares two quantities. To find the ratio of the two boxes:
Ratio of A to B = 
Ratio of A to B = 
= 2
The mass ratio is 2:1 i.e box A has twice the mass of B
Answer: The reaction of benzene with concentrated sulfuric acid at room temperature produces benzenesulfonic acid. The reaction forms a stable carbocation. SO3 being the electrophile
Explanation:
its properties I know it is
hope it help ;)
74 is the answer u find it by subtracting the protons(atomic number) from atomic mas, so basically... 127-53 =74 neutrons
