If we have 321 grams of a liquid, and the density is 0.84 g/mL, then we can easily find the volume of the liquid. We just need to take this 0.84 and multiply that by the number of grams. If we do 321 * 0.84, we get 269.64 mL. This is the volume that this liquid has.Remember this equation for future problems: V = D*M. V meaning volume, D meaning density, and M meaning mass. I hope this helps.
Answer: 0.811m
Explanation: Molarity is the moles of solute present per kg of solvent.
Molar mass of C10H8 = . 128.17 g/mol
No. of moles = given mass/molar mass
11.2g C10H8 = 11.2/128.17 g/mol C10H8
= 0.0874 mol C10H8
NOW 107.8g solvent (chloroform) contains 0.0879 molecules (naphthalene)
1000g '' will contain (0.0879/107.8 x 1000) mole solute
= 0.811 mole
Molarity of the solution is 0.811 m (option A)
The answer is 4. Hope it helps!
<h3>
Answer:</h3>
![\displaystyle K_{eq} = \frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
<h3>
General Formulas and Concepts:</h3>
<u>Chemistry</u>
<u>Aqueous Solutions</u>
<u>Kinetics</u>
<u>Equilibrium</u>
- Equilibrium Reactions RxN ⇄
- Equilibrium Constants
- Equilibrium Expression:
![\displaystyle K = \frac{[Producst]^{coefficients}}{[Reactants]^{coefficients}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K%20%3D%20%5Cfrac%7B%5BProducst%5D%5E%7Bcoefficients%7D%7D%7B%5BReactants%5D%5E%7Bcoefficients%7D%7D)
<h3>
Explanation:</h3>
*Note: Only gases and liquids affect equilibrium
<u>Step 1: Define</u>
[RxN - Balanced] 2H₂O (g) ⇄ 2H₂ (g) + O₂ (g)
<u>Step 2: Identify</u>
[Reactant] H₂O
[Product] H₂
[Product] O₂
<u>Step 3: Write K Expression</u>
- Substitute:
