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EastWind [94]
3 years ago
9

What is the solution for this equation 13m-22=9m-6. This is a equation with variables on both sides

Mathematics
2 answers:
mars1129 [50]3 years ago
8 0
13m-22=9m-6
4m-22=-6
4m=16
m=4
Anon25 [30]3 years ago
6 0
13m-22=9m-6
13m-9m=22-6  <-- integer signs change when it goes to the other side of the  equal to sign
4m=16
m=16/4
<u>m=4</u>    
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This is because using the formula of area for shapes, you get this equation

A=2(wl+hl+hw)=2·(4·6+4·6+4·4)=128

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Carly takes three steps to walk the same distance as jim walks in four steps. each of carly’s steps covers 0. 5 metres. how many
myrzilka [38]

The distance travelled by Jim in 24 step is 9 miles by unitary method.

According to the given question.

The number of steps travelled by Jim = 24

Also, it is given that "Carly takes three steps to walk the same distance as Jim walks in four steps".

Therefore, by unitary mehod we can say that

The number of steps walked by Carly = 3 × (24/4) = 3 × 6  = 18

So, the distance travelled by Carly in 18 steps

= 18 × 0.5miles

= 9 miles

Since, the Carly's 18 steps is equals to Jim's 24 steps.

Therefore, the distance travelled by Jim in 24 step is 9 miles.

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1 year ago
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yuradex [85]

Answer:

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72 = 2^3 \cdot \boxed{3^2}

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3 0
2 years ago
A bag contains five white balls and five black balls. Your goal is to draw two black balls.
umka21 [38]

Answer:

a.) the probability that both the ball drawn are black  = \frac{10}{45} = \frac{2}{9}

b.) Sum of all the probabilities = \frac{\frac{2}{9} }{1 - \frac{2}{9} }  = \frac{\frac{2}{9} }{\frac{8}{9} }  = \frac{2}{8} =\frac{1}{4} = 0.25

Step-by-step explanation:

a) two balls are drawn at random .

   total number of balls   =  10

 number of black balls    =  5

  number of white balls    = 5.

   the number of ways two balls can be drawn = \binom{10}{2}  = \frac{10!}{2! 8!}  = \frac{10\times9}{2}  = 45

  the number of ways two black balls can be drawn = \binom{5}{2}  = \frac{5!}{2! 3!}  = \frac{5\times4}{2}  = 10

   the probability that both the ball drawn are black  = \frac{10}{45} = \frac{2}{9}

b) probability that First draw of two black balls = \frac{2}{9}

  probability that first draw is of two white balls is and second draw is of

  two black balls  = \frac{2}{9} \times\frac{2}{9}

  Probability that first two draws are of white balls and the third draw is of

  two black balls = \frac{2}{9} \times\frac{2}{9} \times\frac{2}{9}

  This is a geometric sequence and the final probability will be the sum of    

  all such probabilities, where we can take the the sequence to be an infinite series and the first term is \frac{2}{9} and the common ratio is \frac{2}{9}  which is less than 1.

  Sum of all the probabilities = \frac{\frac{2}{9} }{1 - \frac{2}{9} }  = \frac{\frac{2}{9} }{\frac{8}{9} }  = \frac{2}{8} =\frac{1}{4} = 0.25

3 0
3 years ago
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