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finlep [7]
3 years ago
9

What is the solubility of argon (in units of grams per liter) in water at 25 °C, when the Ar gas over the solution has a partial

pressure of 0.430 atm? kH for Ar at 25 °C is 1.40×10-3 mol/L·atm.
Chemistry
1 answer:
beks73 [17]3 years ago
5 0

Answer:

0.02405 g/L is the solubility of argon  in water at 25 °C.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{Ar}=K_H\times p_{gas}

where,

K_H = Henry's constant = 1.40\times 10^{-3}mol/L.atm

p_{Ar} = partial pressure of carbonated drink = 0.51atm

Putting values in above equation, we get:

C_{Ar}=1.40\times 10^{-3}mol/L.atm\times 0.430 atm\\\\C_{Ar}=6.02\times 10^{-4}mol/L

Molar mass of argon = 39.95 g/mol

Solubility of the argon gas :

6.02\times 10^{-4}mol/L\times 39.95 g/mol=0.02405 g/L

0.02405 g/L is the solubility of argon  in water at 25 °C.

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Ne4ueva [31]
When the specific heat capacity of the water is 4.18 J/g.°C so, we are going to use this formula to get the heat for cooling three  phases changes from steam to liquid and from liquid to ice (solid) :

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Q is the heat in J

and M is the mass in gram = 1 mol H2O * 18 g/mol(molar mass) = 18 g

C is the specific heat J/g.°C

ΔT is the change in temperature

Q = Mw *[ ( Csteam * ΔTsteam)+(Cw*ΔTw) + (Cice  * ΔT ice)]

    = 18 g * [(2.01 * (155-100°C)) + (4.18 * (100-0°C)) + (2.09 * (0 - 55 °C))]

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and when we know that the heat of fusion for water = 334J/g

and heat of vaporization for water =  2260J/g


∴Q for the two phases changes = M * (2260+334) 

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                                                      = 46692 J 

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5 0
3 years ago
Who was the first to state the concept of an atom
marin [14]
Democritus, a Greek philosopher, first developed the idea of atoms (around 460 B.C., I believe).
Hope this helps!
6 0
3 years ago
A 16.0 mL sample of a 1.04 M potassium sulfate solution is mixed with 14.3 mL of a 0.880 M barium nitrate solution and this prec
stiks02 [169]
Number of moles in the K2SO4 sample
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Since the reaction is a 1:1 ratio between the two reactants, the limiting reagent is the one containing a smaller number of moles, namely Ba(NO3)2.

The molecular mass of BaSO4 is 137.3+(32.06+4*16.00)=233.4
Therefore the theoretical yield of Barium Sulphate is
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Actual yield = 2.60 g (given)
Therefore the percentage yield = 2.60/2.937=88.54%

Answer: 
1. the limiting reagent is Barium Nitrate (Ba(NO3)2)
2. the theoretical yield is 2.94 g
3. the percentage yield is 88.5%

I apologize for the mistake previous to this update.

5 0
2 years ago
If an element has 2+ valence electrons, does it transfer only one or more than one valence electrons​
just olya [345]

Answer:

element having 2+ valence electrons can transfer its more than one electron that is 2 electron completely.

Explanation:

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  • Element  of IIA form ionic with most electronegative element.

Examples:

Cu²⁺, Mg²⁺, Sr²⁺ are examples having  2+ valance electron

one of the following is examples of element that have 2+ valence electrons

MgCl₂

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1s², 2s², 2p⁶, 3s²

or

K =2

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M = 2

So, it have to give its 2 electrons to form a stable compound.

Similarly

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1s², 2s², 2p⁶, 3s², 3p⁵

or

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So, it have to gain one electrons to form a stable compound and complete its octet.

So,

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So one Mg²⁺ and 2 Cl⁻ atoms form an ionic bond

where in this ionic bond Mg²⁺ transfer its 2 valence electron completely and chlorine molecule accept 2 electrons.

                 Cl-----Mg------Cl

So the Answer is

element having 2+ valence electrons can transfer its more than one electron that is 2 electron completely.

8 0
2 years ago
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zhenek [66]
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