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3 years ago

The three types of nuclear radiation in increasing order of penetrating power are ____.

Chemistry

2 answers:

cricket20 [7]3 years ago

5 0

Answer:

The three types of nuclear radiation in increasing order of penetrating power are ____.

alpha, beta, gamma

Explanation:

Alpha Ray: This has the least penetrating power because the particles produced during decay are large in quantity but they have a very low energy which dosent alow them to move far through space because the are ususally blocked.

Beta ray : they have more penetrating power than alpha rays because they a bit higher in energy and quantity {size}

Gamma Ray; this has the most penetrating power. they are highly powerful waves but do little at ionization of other atoms or molecules. it penetrates through molecules very easily due to its size and energy.

sveta [45]3 years ago

5 0

Answer:

Alpha, Beta, Gamma

Explanation:

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At constant pressure, which of these systems do work on the surroundings? A ( s ) + B ( s ) ⟶ C ( g ) A(s)+B(s)⟶C(g) 2 A ( g ) +

Tju [1.3M]

Correct question:

At constant pressure, which of these systems do work on the surroundings?

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

(d) 2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

Answer:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

Explanation:

Work done by a system on the surroundings at a constant pressure is given as;

W = -PΔV

Where;

ΔV is gas expansion, that is final volume of the gas minus initial volume of the gas must be greater than zero.

Part (a)

A ( s ) + B ( s ) ⟶ C ( g )

ΔV = 1 - (0) = 1 (expansion)

Part (b)

2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

ΔV = 5 - ( 2+ 2) = 1 (expansion)

Part (c)

A ( g ) + B ( g ) ⟶ C ( g )

ΔV = 1 - ( 1 + 1) = -1 (compression)

Part (d)

2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

ΔV = 3 - ( 4) = -1 (compression)

Thus, systems where there is gas expansion are in part (a) and part (b). The correct answers are:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

4 0

3 years ago

If the half-life of a sample of a radioactive substance is 30 seconds, how much would be left after 60 seconds? A. one-fourth B.

Basile [38]

$m=m_{0}*(\frac{1}{2})^{\frac{60}{30}}\\\\
m=m_{0}*(\frac{1}{2})^{2}\\\\
m=\frac{1}{4}m_{0}$

If the half-life of a sample of a radioactive substance is 30 seconds, how much would be left after 60 seconds? <span>A. one-fourth</span>

7 0

3 years ago

Read 2 more answers

To convert 20 g of ice at -10°C to 110°C to steam you need<br> cal of energy?

shtirl [24]

Answer:

29,200 cal = 1.22 E 5 joules

Explanation:

hope this helps

6 0

3 years ago

How many grams of Fe2+ are there in 0.003109 moles of Fe2+?

Sergio [31]

Answer: 0.174 g

Explanation:

First of all understand that charge on an atom like here 2+ will not vary molar mass. because ions are formed by loss or gain of electrons and electrons do not contribute to the mass of an atom or ion. so losing or gaining electron doesnt create any difference.

molar mass of Fe, i.e. mass of 1 mole of Fe is 56 g. So, mass of 1 mole of Fe2+ will also be 56 g.

given is 0.003109 moles of Fe2+,

Use maths,

1 mole of Fe2+ weighs 56 g

So, 0.003109 moles will weigh = (56 g / 1 mol ) x 0.003109 = 0.174 g.

7 0

3 years ago

can a light object that was hit with a small force accelerate as rapidly as a heavier object hit with a big force? why or why no

Tcecarenko [31]

The acceleration is defined by force divided by the mass of the object. So, When the smaller object is hit by a small force, it can produce equal acceleration which is same as that of the bigger body hit with large force.

<h3><u>Explanation:</u></h3>

Force is defined as the product of the mass of the body its applied to and the acceleration of the body in the direction of the force. So acceleration is force divided by the mass of the body.

Let the mass of the smaller body be m and that of the larger body be M.

The smaller force applied on the smaller body be f and the larger force applied on the larger body be F.

So acceleration of the larger body = F/M.

Acceleration of the smaller body = f/m.

For the accelerations to be same,

F/M = f/m.

Or F/f = M/m.

So when the ratio of the force applied on two bodies is in ratio of their masses, the acceleration becomes equal.

3 0

3 years ago