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77julia77 [94]
3 years ago
9

Pleasee help from anyone

Mathematics
2 answers:
Brut [27]3 years ago
6 0

Answer:

discriminant = 120

2 real roots ( or 2 x intercepts)

Step-by-step explanation:

f(x) = -7x^2 +8x+2

The discriminant is

b^2-4ac

Where ax^2 +bx+c

so a = -7  b = 8 and c =2

(8)^2 -4(-7) *(2)

64 +56

120

If the discriminant is >0 we have 2 real roots

If the discriminant =0 we have 1 real root

If the discriminant <0 we have 2 complex root ( or no real roots)

Margaret [11]3 years ago
4 0

Answer:

18 and 22.8 will be your answer

Step-by-step explanation:


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Answer: 8

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2 years ago
A number line going from negative 4 to positive 4. What is the distance between 0 and –2? Use the number line to answer the ques
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3 years ago
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12 friends share four pizzas equally what fraction of the pizza does each friend get
KonstantinChe [14]

Since 12 friends share four pizzas equally,

3 friends share a pizza equally.

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The ratio of sixth graders to seventh graders at the school dance is 2 to 3.
Inessa [10]

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6 0
2 years ago
Evaluate the integral of the quotient of the cosine of x and the square root of the quantity 1 plus sine x, dx.
VMariaS [17]

Answer:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.

Step-by-step explanation:

In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.

Let u = 1 + sin(x).

This means du/dx = cos(x). This implies dx = du/cos(x).

Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.

∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))

= ∫(u^(-1/2) * du). Integrating:

(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.

Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!

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2 years ago
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