A 0.2-kg ball moving at 2.0 m/s perpendicular to a wall rebounds from the wall at 1.5 m/s. The impulse given to the ball is:
1 answer:
Answer:
J = 0.7 N-s away from wall
Explanation:
Given that,
Mass of the ball, m = 0.2 kg
Initial speed of the ball, u = 2 m/s
Final speed of the ball, v = -1.5 m/s (as it rebounds)
Impulse is equal to the change in momentum. So,
So, the impulse given to the ball is 0.7 N-m and it is away from the wall. Hence, the correct option is (c).
You might be interested in
Answer: A student walks 50 meters east, 40 meters north, 35 meters east, and then 20 m south. Then the magnitude and direction of the student's total displacement will be 87.32 m along the direction of AD or in east-south direction.
Explanation: To find the correct answer, we need to know about the Displacement of a body in motion.
<h3>What is displacement of a body in motion?</h3>- The displacement is the shortest distance between initial and final positions of a body.
- It's a vector quantity, and can positive, negative, or zero.
- The magnitude of displacement is less than or equal to the distance travelled.
- At first, we can draw a diagram showing the motion of the body.
- From the diagram, the displacement of the body will be equal to the distance between point A and D.
- To solve this, we can use Pythagoras theorem.
Thus, from the above calculations, we can conclude that, the displacement of the body will be equal to 87.32 m along the direction of AD or in east-south direction.
Learn more about the Displacement here:
#SPJ4
