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3 years ago

Why is an atom considered electrically neutral?

Chemistry

2 answers:

sveticcg [70]3 years ago

8 0

Explanation:

A proton and an electron have an equal amount but an opposite type of charge. Thus, if an atom contains equal numbers of protons and electrons, the atom is described as being electrically neutral.

Aleks04 [339]3 years ago

4 0

Answer:

Explanation:

A proton and an electron have an equal amount but an opposite type of charge. Thus, if an atom contains equal numbers of protons and electrons, the atom is described as being electrically neutral.

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The density of copper is 8.92 g/cm^3. If you plotted the mass of copper in grams versus the volume in cubic centimeters, what wo

dybincka [34]

The slope would be 8.92g/cm^3.

D = m/V

m = DV

The equation for a straight line is

y = mx +b, where m is the slope and b is the y-intercept. We have

m = DV + 0

Thus, a plot of m vs V will give a straight line with a slope of D and a

y-intercept at the origin.

Slope = D = 8.92g/cm^3

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3 years ago

Consider the following chemical reaction: H2 (g) + I2 (g) 2HI (g) At equilibrium in a particular experiment, the concentrations

bearhunter [10]

The question is incomplete, here is the complete question:

Consider the following chemical reaction: H₂ (g) + I₂ (g) ⇔ 2HI (g) At equilibrium in a particular experiment, the concentrations of H₂, I₂, and HI were 0.15 M, 0.033 M and 0.55 M respectively. The value of Keq for this reaction is

Answer: The value of $K_{eq}$ for the given reaction is 61.11

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_[eq}$

For a general chemical reaction:

$aA+bB\rightarrow cC+dD$

The expression for $K_{eq}$ is written as:

$K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

For the given chemical equation:

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

The expression of $K_{eq}$ for above equation follows:

$K_{eq}=\frac{[HI]^2}{[H_2][I_2]}$

We are given:

$[HI]_{eq}=0.55M$

$[H_2]_{eq}=0.15M$

$[I_2]_{eq}=0.033M$

Putting values in above expression, we get:

$K_{eq}=\frac{(0.55)^2}{0.15\times 0.033}\\\\K_{eq}=61.11$

Hence, the value of $K_{eq}$ for the given reaction is 61.11

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4 years ago

a person tries to catch a bus to see how it starts; in a desperate attempt, he starts running with a speed of 6m / s. When you a

Brut [27]

Answer:

I dont know

Explanation:

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3 years ago

What is 0.00034 in exponential form

Verizon [17]

Answer:

3.4 × 10 ^− 4

Explanation:

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10 . If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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kkurt [141]

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3 years ago