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3 years ago

11

I need help on 7 and 8 thanks

1 answer:

Sauron [17]3 years ago

5 0

8. 107.1 MHz

7. 90.5 MHz

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Gold has a density of 19.3 g/cm3. I fyou has a 2.00 cm3 block of gold, what would be its mass?

dalvyx [7]

Density equals mass × volume

d=m/V

then m=d×V=19.3×2=38.6g

m=38.6g

hope this helps you

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3 years ago

When driving at night switch to low-beams whenever you come within ___ ft of an oncoming vehicle.

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2 years ago

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Calculate the average speed of a gazelle that runs 140 meters in 5.0 seconds.

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How do you convert from picoseconds to milliseconds using the conversion factors?

andrew11 [14]

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3 years ago

A 3-m-high, 7-m-wide rectangular gate is hinged at the top edge and is restrained by a fixed ridge. Determine the hydrostatic fo

Shalnov [3]

Answer:

The Hydrostatic force is $F = 137.2 kN$

The location of pressure center is $Z = 1.333 \ m$

Explanation:

From the question we are told that

The height of the gate is $h = 3 \ m$

The weight of the gate is $w = 7 \ m$

The height of the water is $h_w = 2 \ m$

The density of water is $\rho_w = 1000 \ kg/m^3$

Note used $h_w$ for height of water and height of gate immersed by water since both have the same value

The area of the gate immersed in water is mathematically represented as

$A = h_w * w$

substituting values

$A = 2* 7$

$A = 14 \ m^2$

The hydrostatic force is mathematically represented as

$F = \rho_w * g * h_f * A$

Where

$h_f =h- h_w$

$h_f =3 -2$

$h_f = 1\ m$

So

$F = 1000 * 9.8 * 1 * 14$

$F = 137.2 kN$

The center of pressure is mathematically represented as

$Z = h_f + \frac{I_g}{h_f * A}$

Where $I_g$ is the moment of inertia of the gate which mathematically represented as

$I_g = \frac{w * h_w^2}{12}$

The $h_w$ is the height of gate immersed in water

$I_g = \frac{7 * 2^2 }{12}$

$I_g = 4.667\ kg m^2$

Thus

$Z = 1 + \frac{4.66}{1 * 14}$

$Z = 1.333 \ m$

3 0

2 years ago