Answer:
B.
Explanation:
It is brittle like a nonmetal but conducts electricity and heat like a metal.
It was the meaning of "tiny" in Greek then... atomus
Explanation:
The only flaw I can find is you squared 3 instead of cubing it and it will be 27X^4 instead of 9x^4.
This reduces the amount slightly, but the number is still incredibly high (about 10 ^ 5 L is what I've calculated). Your professor might want to point out that this will not be a effective experiment due to the large volume of saturated
The Ksp value of Ca(OH)2 on the site (I used 5.5E-6 [a far more soluble compound than Al(OH)3]) and estimated how much of it will be needed. My calculation was approximately 30 ml. If you were using that much in the experiment, it implies so our estimates for Al(OH)3 are right, that the high amount is unreasonably big and that Al(OH)3 will not be a suitable replacement unless the procedure was modified slightly.
Answer:
The molarity of ZnCl2 is 1.699 mol/ L.
Explanation:
Balance chemical equation:
Zn(s) + CuCl2(aq) → ZnCl2(aq) + Cu(s)
Given data:
mass of zinc = 30 g
total volume of solution = 270 mL
molarity of ZnCl2 = ?
Solution:
First of all we will calculate the moles of Zn.
molar mass of zinc = 65.38 g/mol
number of moles = mass / molar mass
number of moles = 30 g/ 65.38 g/mol
number of moles = 0.4588 mole
From the balance chemical equation we will compare the moles of Zn and ZnCl2
Zn : ZnCl2
1 : 1
0.4588 : 0.4588
The number of moles of ZnCl2 are 0.4588 mol.
Molarity of ZnCl2:
Total volume of solution is 270 mL. We will convert it into liter.
1 L = 1000 mL
270/1000 = 0.27 L
Molarity = moles of solute / volume of solution in liter
Molarity = 0.4588 mol / 0.27 L
Molarity = 1.699 mol/ L