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Deffense [45]
3 years ago
10

Lee dissolved 8 grams of a salt in a certain amount of water to obtain 608 grams of salt solution. What was the mass of the wate

r used to make the solution?
Chemistry
2 answers:
earnstyle [38]3 years ago
6 0
600 Grams 
I'm Pretty sure at least

xenn [34]3 years ago
4 0

Answer: 600 g of the water was used to make the salt solution.

Explanation:

In a salt solution ,salt is present as a solute and water as a solvent.

Mass of salt present in the solution = 8 g

Mass of the salt solution = 608 g

Solution = Solvent + Solute

608 g = solvent + 8 g

Mass of water = 608 g - 8 g= 600 g

600 g of the water was used to make the salt solution.

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An acidic solution at 25°c will have a hydronium ion concentration ________ and a ph value ________.
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The given question is incomplete. The complete question is:

An acidic solution at 25°C will have a hydronium ion concentration ________ and a pH value ________.

[H_3O^+] > 1\times 10^{-7} M, pH < 7.00

[H_3O^+] < 1\times 10^{-7}, pH < 7.00

[H_3O^+] < 1\times 10^{-7},, pH > 7.00

[H_3O^+] > 1\times 10^{-7},, pH > 7.00

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Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.

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As pH of acids is less than 7, the hydronium ion concentration is greater than

Thus the correct option is [H_3O^+] > 1\times 10^{-7} M, pH < 7.00

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