Answer:
0.4762 J/g°C.
Explanation:
<em>The amount of heat released to water = Q = m.c.ΔT.</em>
where, m is the mass of water (m = 15.0 g).
c is the specific heat capacity of water = ??? J/g°C.
ΔT is the temperature difference = (final T - initial T = 37.0°C - 30.0°C = 7.0°C).
<em>∴ The specific heat capacity of water = c = Q/m.ΔT</em> = (50.0 J)/(15.0 g)(7.0°C) = <em>0.4762 J/g°C.</em>
Flame test is a qualitative test which is used to identify the metal and metalloid ion in the sample.
<h3>What is Flame Test ?</h3>
A Flame test is used to identify the metal and metalloid ion in the sample. Flame test is a qualitative test. Not every metal ion emit color when it is heated in the gas burner.
<h3>What is the Purpose of Flame test ?</h3>
The purpose of flame test is used to find the identities of ions in two solutions of unknown composition by comparing the colors they produce.
<h3>What are the material used ?</h3>
- Bunsen Burner
- Matches
- Gloves
- Weighing dishes
- Beakers
Thus from the above conclusion we can say that Flame test is a qualitative test which is used to identify the metal and metalloid ion in the sample.
Learn more about the Flame test here: brainly.com/question/864891
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Answer:
1.48L
Explanation:
From the question given, we obtained the following data:
V1 (initial volume) = 2.50L
T1 (initial temperature) = 308K
P1 (initial pressure) = 1.15atm
P2 (final pressure) = 1.80atm
T2 (final temperature) = 286K
V2 (final volume) =..?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the gas can obtain as follow:
P1V1/T1 = P2V2/T2
1.15 x 2.5/308 = 1.8 x V2/286
Cross multiply to express in linear form:
308 x 1.8 x V2 = 1.15 x 2.5 x 286
Divide both side by 308 x 1.8
V2 = (1.15 x 2.5 x 286)/(308 x 1.8)
V2 = 1.48L
Therefore, the new volume of the gas is 1.48L
The correct answer is IE decreases down the group.
On moving down the group, the size of the element increases due to the increase in the number of shells. The element with smallest size has less the attraction of the nucleus on the valance electron. It needs more energy to remove an electron from its valance shell. Hence, the IE decreases down the group.
Why does ionization energy increase down the group but decreases going across a period?
Because there are more protons with time, the ionization energy rises. As a result, there will be more attraction because the nuclear charge has increased.
Even if there is stronger attraction, one should be aware that the shielding effect and distance from the nucleus remain largely constant. The same primary quantum shell contains all of the valence electrons, which explains this.
Therefore, while distance from the nucleus and the shielding effect stay fairly constant, an increase in nuclear charge causes an increase in attraction and increases the energy required to remove an electron.
The ionization energy drops with each group. This is because the outside electrons acting as a shield or screen for the nucleus make the attraction between them weaker and make it easier for them to be withdrawn.
To learn more about ionization energy refer the link:
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Answer:
amino groups
Explanation:
The cellular respiration pathways are central in the extraction of energy from all these different molecules. Amino acids, lipids and other carbohydrates can become different intermediates of glycolysis and the citric acid cycle; this allows them to enter the path of cellular respiration through other different doors. Once these molecules enter the pathway, there is no difference due to their origin: they simply continue through the remaining steps and produce NADH, FADH2 and ATP
When you eat proteins, your body has to break them down into amino acids before they can be used by your cells. Most of the time, amino acids are recycled and used to form new proteins, they do not oxidize as fuel.
However, if there are more amino acids than the body needs or if the cells are fasting, some amino acids are degraded for energy purposes by cellular respiration. In order to enter cellular respiration, amino acids must first get rid of their amino group. This step generates ammonia (NH
3) as a waste product, which - in humans and other mammals - is converted to urea and removed from the body through urine.
