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nikklg [1K]
3 years ago
3

Assume that the x components of the blocks' momenta at a certain moment are p1x and p2x. find the x component of the velocity of

the center of mass (vcm)x at that moment. express your answer in terms of m1, m2, p1x, and p2x.
Physics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

Explanation:

The amount of movement is the product of the mass of a body because of its speed, the speed is that of the center of mass; The equation is:

    p = mv

Where v is the velocity of the center of mass of the body, what we have to do is clear the velocity

      V = p / m

  It is our case for each body and as the amount of movement is a vector we must write it for each axis

   V1x = p1x / m1

   V2x = p2x / m2

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Jack and Jill are on two different floors of their high rise office building and looking out of their respective windows. Jack s
Maru [420]

Answer:

a) speed when Jack sees the pot : 12.92 meters per second

b) height difference 163.115 meters

Explanation:

First to calculate te initial speed we use the acceleration formula:

a= v1-v0/t

Acceleration being gravity's acceleration (9.8 m/s^2)

v1 being the speed when Jill sees the pot

v0 when Jack sees it

and t the time between

Solving for v0 it would be

v1 - a*t = v0

replacing

58 m/s -  9.8 m/s^2 *4.6 s = v0 = 12.92 m/s

For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)

The formula is

y0 + v0*t + 1/2 g *t^2 = yt

replacing

0m + 12.92m/s* 4.6 s + 1/2 * 9.8 m/s^2 * (4.6 s)^2 = 163.115 m

5 0
3 years ago
A skater rotates with her arms crossed at an angular speed of 8.0 rad/s and she has a moment of inertia of 100 kg/m2. She extend
solong [7]

Answer:

When her hands extends, her momen of inertia is 4.28\ kg-m^2.

Explanation:

Given that,

Initial angular speed, \omega_i=8\ rad/s

Initial moment of inertia, I_1=100\ kg-m^2

Final angular speed, \omega_f=7\ rad/s

Initially, a skater rotates with her arms crossed and finally she extends her arms. The momentum remains conserved. Using the conservation of momentum as :

I_1\omega_1=I_2\omega_2

I_2 is final moment of inertia

I_2=\dfrac{I_1\omega_1}{\omega_2}\\\\I_2=\dfrac{100\times 8}{7}\\\\I_2=114.28\ kg-m^2

So, when her hands extends, her momen of inertia is 4.28\ kg-m^2. Hence, this is the required solution.

7 0
3 years ago
Garrett Hardin's "Tragedy of the Commons" describes the tendency of people to overuse publicly-owned natural resources until the
Aliun [14]

Answer:

is it bad if i keep thinking about p ussy

Explanation:

8 0
3 years ago
A circular wire loop of radius 15.0 cm carries a current of 2.60
Korolek [52]
Part (a): Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
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4 years ago
In objects motion will not change is the force is acting on the object are blank
maks197457 [2]
An object in motion stays in motion while an object at rest stays at rest.
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