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nikklg [1K]
3 years ago
3

Assume that the x components of the blocks' momenta at a certain moment are p1x and p2x. find the x component of the velocity of

the center of mass (vcm)x at that moment. express your answer in terms of m1, m2, p1x, and p2x.
Physics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

Explanation:

The amount of movement is the product of the mass of a body because of its speed, the speed is that of the center of mass; The equation is:

    p = mv

Where v is the velocity of the center of mass of the body, what we have to do is clear the velocity

      V = p / m

  It is our case for each body and as the amount of movement is a vector we must write it for each axis

   V1x = p1x / m1

   V2x = p2x / m2

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A man stands on top of a cliff and shouts.
satela [25.4K]

\small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x

\small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return =  \frac{2x}{v}  = 1

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When driving at night, only use your high-beam headlights___
zzz [600]

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B

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6 0
3 years ago
Boxes A and B are being pulled to the right on a frictionless surface. Box A has a larger mass than B. How do the two tension fo
Vlad1618 [11]

Answer:

Tension T1 is less than tension T2.

T1 < T2

Explanation:

According to given data,

mass of box A ( mA) is grater than mass of box B (mB)

we can write,

m(A) > m(B)

Newton's second law states that:

Tension of object is directly proportional to the mass of the system.

T ∝ m

here Boxes A and B are being pulled to the right on a frictionless surface,

so Tension T1 generates due to the mass of box A m(A)

and Tension T2 arises due to mass of the system m(A) + m(B)

Thus tension T1 will be less than tension T2

T1 < T2

learn more about Tension force here:

<u>brainly.com/question/13175014</u>

<u />

#SPJ4

8 0
2 years ago
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