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nikklg [1K]
3 years ago
3

Assume that the x components of the blocks' momenta at a certain moment are p1x and p2x. find the x component of the velocity of

the center of mass (vcm)x at that moment. express your answer in terms of m1, m2, p1x, and p2x.
Physics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

Explanation:

The amount of movement is the product of the mass of a body because of its speed, the speed is that of the center of mass; The equation is:

    p = mv

Where v is the velocity of the center of mass of the body, what we have to do is clear the velocity

      V = p / m

  It is our case for each body and as the amount of movement is a vector we must write it for each axis

   V1x = p1x / m1

   V2x = p2x / m2

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Alpha particles, each having a charge of +2e and a mass of 6.64 ×10-27 kg, are accelerated in a uniform 0.50 T magnetic field to
sergij07 [2.7K]

Answer:

KE=1.2036\times 10^{-12}\ J

Explanation:

Given:

  • charge on the alpha particle, q=2e=3.2\times 10^{-19}\ C
  • mass of the alpha particle, m=6.64\times 10^{-27}\ kg
  • strength of a uniform magnetic field, B=0.5\ T
  • radius of the final orbit, r=0.5\ m

<u>During the motion of a charge the magnetic force and the centripetal forces are balanced:</u>

q.v.B=m.\frac{v^2}{r}

m.v=q.B.r

where:

v = velocity of the alpha particle

v=\frac{q.B.r}{m}

v=\frac{3.2\times 10^{-19}\times 0.5\times 0.5}{6.64\times 10^{-27}}

v=1.2048\times 10^{7}\ m.s^{-1}

Here we observe that the velocity of the aprticle is close to the velocity of light. So the kinetic energy will be relativistic.

<u>We firstly find the relativistic mass as:</u>

m'=\frac{1}{\sqrt{1-\frac{v^2}{c^2} } } \times m

m'=\frac{6.64\times 10^{-27}}{\sqrt{1-\frac{(1.2048\times 10^7)^2}{(3\times 10^8)^2} } }

m'=6.6533\times10^{-27}\ kg

now kinetic energy:

KE=m'.c-m.c

KE=6.6533\times 10^{-27}\times (3\times 10^8)^2-6.64\times 10^{-27}\times (3\times 10^8)^2

KE=1.2036\times 10^{-12}\ J

6 0
3 years ago
Which of the following has the most biomass? a. quaternary consumers b. secondary consumers c. primary consumers d. producers
elena-s [515]
<h3><u>Answer;</u></h3>

<em>Producers </em>

<h3><u>Explanation;</u></h3>
  • <u><em>Producers </em></u>occupy the lowest level in any food chain or food web. They are the organisms that all other organisms in the food chain rely on.
  • <em><u>Producers </u></em>have the ability to make their own food through the process of photosynthesis where they use energy from sunlight, together with water and carbon dioxide to generate food.
  • The ability of producers to make their own food and the fact that they occupy the lowest level in a food chain means <em><u>they have the highest biomass.</u></em>
4 0
4 years ago
Read 2 more answers
A flashlight beam makes an angle of 60 degrees with the surface of the water before it enters the water. In the water what angle
vekshin1

Answer:

θ₂ = 40.5º

Explanation:

For this exercise we must use the law of refraction

         n₁ sin θ₁ = n₂ sin θ₂

where index 1 is for the incident ray and index 2 is for the refracted ray

in this case the incident ray has an angle of θ₁ = 60º and the refractive index of the water is

          n₂ = 1,333

        sin θ₂ = \frac{n_1}{n_2} \   sin \theta_1

let's calculate

        sin  θ₂ = 1 / 1.3333 sin 60

        sin θ₂ = 0.64968

        θ₂ = sin⁻¹ (0.64968)

        θ₂ = 40.5º

8 0
3 years ago
Approximately how much energy is contained in 1 g of matter?
aleksley [76]

Option (B) is correct.Energy contained in one gram of matter=9 x 10¹³ J

Explanation:

mass= 1 g= 0.001 kg

c= velocity of light= 3 x 10⁸ m/s

The mass energy equivalence equation is given by

E = m C²

E= (0.001)(3 x 10⁸)²

E=9 x 10¹³ J

Thus energy contained in one gram of matter=9 x 10¹³ J

7 0
3 years ago
A fly has a mass of 1 gram at rest. how fast would it have to be traveling to have the mass of a large suv, which is about 3000
Zigmanuir [339]

We solve this using special relativity. Special relativity actually places the relativistic mass to be the rest mass factored by a constant "gamma". The gamma is equal to 1/sqrt (1 - (v/c)^2). <span>

We want a ratio of 3000000 to 1, or 3 million to 1. 

</span>

<span>Therefore:
3E6 = 1/sqrt (1 - (v/c)^2) 
1 - (v/c)^2 = (0.000000333)^2 
0.99999999999999 = (v/c)^2 
0.99999999999999 = v/c 
<span>v= 99.999999999999% of the speed of light ~ speed of light
<span>v = 3 x 10^8 m/s</span></span></span>

8 0
4 years ago
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