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SpyIntel [72]
3 years ago
10

What the resalut H2SO4 +CO3-=?

Chemistry
1 answer:
BartSMP [9]3 years ago
6 0

Answer:

H2SO4 + CO3 = H2CO3 + SO4

Explanation:

H2SO4 + CO3

This is the reaction of sulphuric acid and carbon trioxide.

Balanced reaction is;

H2SO4 + CO3 = H2CO3 + SO4

So they react to produce carbonic acid and sulfate.

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Lerok [7]

Answer: Beavers

Explanation: they do not hibernate

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7 0
2 years ago
Why were they put into water before we tested them?
klasskru [66]

explain the question your asking

7 0
3 years ago
Read 2 more answers
A 5.000 g sample of Niso4 H2O decomposed to give 2.755 g of anhydrous NiSO4.
Vinvika [58]

Answer:

a) 7.0.

b) Nickel sulfate hepta hydrate.

c) 280.83 g/mol.

d) 44.9%.

Explanation:

<u><em>a) What is the formula of the hydrate?</em></u>

The mass of the hydrated sample (NiSO₄.xH₂O) = 5.0 g,

The mass of the anhydrous salt (NiSO₄) = 2.755 g,

The mass of water = 5.0 g - 2.755 g = 2.245 g.

∴ no. of moles of water = mass/molar mass = (2.245 g)/(18.0 g/mol) = 0.1247 mol.

∴ no. of moles of anhydrous salt (NiSO₄) = mass/molar mass = (2.755 g)/(154.75 g/mol) = 0.0178 mol.

∴ water of crystallization in the sample (x) = no. of moles of water/no. of moles of anhydrous salt (NiSO₄) = (0.1247 mol)/(0.0178 mol) = 7.0.

<u><em>b) What is the full chemical name for the hydrate?</em></u>

The name of the salt (NiSO₄.7H₂O) is Nickel sulfate hepta hydrate.

<u><em>c) What is the molar mass of the hydrate? </em></u>

(NiSO₄.7H₂O)

The molar mass = molar mass of NiSO₄ + 7(molar mass of H₂O) = (154.75 g/mol) + 7(18.0 g/mol) = 280.83 g/mol.

<em><u>d) What is the mass % of water in the hydrate?</u></em>

The mass % of water = (mass of water)/(mass of hydrated sample) x 100 = (2.245 g)/(5.0 g) x 100 = 44.9%.

8 0
3 years ago
n a coffee cup calorimeter, 100.0 mL of 1.0M NaOH and 100.0 mL of 1.0M HCl are mixed. Both solutions were originally at 24.6 deg
RoseWind [281]

Answer:

Explanation:

mass of the solution = volume x density = 200 x 1 = 200 gm

heat absorbed = m x s x Δ t , s is specific heat , Δt is rise in temperature

= 200 x 4.18 x ( 31.3 - 24.6 )

= 5601 J .

This is the enthalpy change required.

3 0
3 years ago
1. How would the series of figures change in the presence of a catalyst?
statuscvo [17]

No, it won't change the amount of reactants nor the products as a catalyst will only provide an alternative path where lower activation energy is needed for the process to take place.

hope this explains it

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8 0
2 years ago
Read 2 more answers
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