Answer:
Mass = 14.72 g
Explanation:
Given data:
Volume of hydrogen = 6.58 L
Temperature of gas = 32°C (32+273 = 305 k)
Pressure of gas = 895 mmHg (895/760 = 1.2 atm)
Mass of sodium required = ?
Solution:
Chemical equation:
2HCl + 2Na → 2NaCl + H₂
Number of moles of hydrogen:
PV = nRT
1.2 atm × 6.58 L = n× 0.0821 atm.L/mol.K×305 K
7.9 atm.L = n× 25.0 atm.L/mol
n = 7.9 atm.L / 25.0 atm.L/mol
n = 0.32 mol
Now we will compare the moles of hydrogen with sodium.
H₂ : Na
1 : 2
0.32 : 2/1×0.32 = 0.64 mol
Mass of sodium:
Mass = number of moles × molar mass
Mass = 0.64 mol × 23 g/mol
Mass = 14.72 g
There are 22 neutrons in an argon atom. you simply subtract the proton count (atomic number) from the average atomic mass. WORK: 40-18=22
Answer:
The value of Ka 
It is a weak acid
Explanation:
From the question we are told that
The concentration of ![[HClO_2]=0.24M](https://tex.z-dn.net/?f=%5BHClO_2%5D%3D0.24M)
The concentration of ![[H^+]=0.051M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.051M)
The concentration of ![[ClO_2^-]=0.051M](https://tex.z-dn.net/?f=%5BClO_2%5E-%5D%3D0.051M)
Generally the equation for the ionic dissociation of 
is
The equilibrium constant is mathematically represented as
![= \frac{[H^+][ClO_2^-]}{[HClO_2]}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%5BH%5E%2B%5D%5BClO_2%5E-%5D%7D%7B%5BHClO_2%5D%7D)
Substituting values since all value of concentration are at equilibrium
Since the value of is less than 1 it show that in water it dose not completely
disassociated so it an acid that is weak
You have 3.498 moles of the gas/neon
To get the theoretical yield of ammonia NH3:
first, we should have the balanced equation of the reaction:
3H2(g) + N2(g) → 2NH3(g)
Second, we start to convert mass to moles
moles of N2 = N2 mass / N2 molar mass
= 200 / 28 = 7.14 moles
third, we start to compare the molar ratio from the balanced equation between N2 & NH3 we will find that N2: NH3 = 1:2 so when we use every mole of N2 we will get 2 times of that mole of NH3 so,
moles of NH3 = 7.14 * 2 = 14.28 moles
finally, we convert the moles of NH3 to mass again to get the mass of ammonia:
mass of NH3 = no.moles * molar mass of ammonia
= 14.28 * 17 = 242.76 g
