Answer:GASEOUS, LOWERING ,EMITTED AS HEAT, DOWN,DO NOT RELEASE,DECREASES,NEGATIVE.
Explanation: Filling the blanks gives
Lattice energy is associated with forming a crystalline lattice of alternating cations and anions from the _GASEOUS___________ ions.
Because the cations are positively charged and the anions are negatively charged, there is a LOWERING of potential- as described by Coulomb's law-when the ions come together to form a lattice energy.That energy is EMITTED AS HEAT when the lattice forms.
As the ionic radii increases as you move DOWN a group, ions cannot get as close to each other and therefore DO NOT RELEASE as much energy when the lattice forms. Thus the lattice energy DECREASES (becomes less) NEGATIVE as the radius increases.
The above gives the definition of Lattice Energy and how it relates to atomic and ion charge.
<span>1.
</span>The balanced reaction is:<span>
Mg (s) + 2HCl (aq)
--> MgCl 2 (aq) + H 2 (g)
We
are given the amount hydrochloric acid to be used for the reaction. This will
be the starting point of the calculation.
40.0 g
HCl ( 1 mol HCl / 36.46 g HCl)
(1 mol H2 / 2 mol HCl) (2.02 g H2 / 1 mol H2) = 1.11 g H2</span>
A substance that increases rate of rxn by changing orientation of molecules and/or activation energy. both increase effectivity of collisions.
By adding together the number of protons and neutrons and multiplying by 1 amu, you can calculate the mass of the atom
Answer:
Qc <Kc and the system will evolve to the right.
Explanation:
The reaction constant Qc is calculated when a reaction that has not yet reached equilibrium and allows determining where the reaction will move to reach equilibrium. For the following reaction:
aA + bB ⇔ cC + dD
the constant Qc is calculated as:
![Qc=\frac{[C]^{c}*[D]^{d} }{[A]^{a} *[B]^{b} }](https://tex.z-dn.net/?f=Qc%3D%5Cfrac%7B%5BC%5D%5E%7Bc%7D%2A%5BD%5D%5E%7Bd%7D%20%20%7D%7B%5BA%5D%5E%7Ba%7D%20%2A%5BB%5D%5E%7Bb%7D%20%7D)
Comparing Qc with Kc allows to find out the status and evolution of the system:
If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.
If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.
If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.
In this case:
![Qc=\frac{[NaCl]*[H_{2}O] }{[HCl]*[NaOH]}](https://tex.z-dn.net/?f=Qc%3D%5Cfrac%7B%5BNaCl%5D%2A%5BH_%7B2%7DO%5D%20%7D%7B%5BHCl%5D%2A%5BNaOH%5D%7D)
Being:
- [NaCl] = 1.75 M
- [H₂O] = 1 M
- [HCl] = 2.5 M
- [NaOH] = 3.5 M
Replacing:

Solving:
Qc=0.2
Being Kc = 0.5, then <u><em>Qc <Kc and the system will evolve to the right.</em></u>