Kepler's second law of planetary motion<span> describes the speed of a </span>planet<span> traveling in an elliptical orbit around the sun. It states that a line between the sun and the </span>planetsweeps equal areas in equal times. Thus, the speed of theplanet<span> increases as it nears the sun and decreases as it recedes from the sun.</span>
Answer:
Speed = 0.00392 m/s
Explanation:
Solution:
Frequency of the radio = 85 MHz
If we have the frequency, we can calculate the wavelength of the radio wave.
As we know,
Frequency = speed of light/wavelength
wavelength = c/f
c = speed of light = 3 x 
m/s
So,
Wavelength = 3 x m/s / 85 x 
Hz
Wavelength = 3.5294 m
Man gets disturbed reception at t = 15 min
t = 15 x 60 = 900 s
t = 900 s
Speed = distance/time
Here, distance is wavelength. So,
Speed = 3.5294 m / 900 s
Speed = 0.00392 m/s
Hence, the man's car is going with speed of 0.00392 m/s
First calculate the time it would take for the crate to
fall using the formula:
h = v0 t + 0.5 g t^2
110 m = 0 + 0.5 (9.8 m/s^2) t^2
t = 4.74 s
The crate is also moving at 46 m/s on with respect to the
horizontal surface, therefore distance covered is:
d = (46 m/s) * 4.74 s
d = 217.95 m
The crate would fall 217.95 m from the tail of the car.
Answer:
Explanation:
Basically the star slowly burns its hydrogen into Helium. Depending on the mass, the star will have a turbulent core where the Helium will be fully mixed or a radiative core where the helium will settle at the centre (remember it's heavier than Hydrogen). The second case is what happens in the Sun.
I am fairly certain it's D. Good luck!
