On the planet Xenophous a 1.00 m long pendulum on a clock has a period of 1.32 s. What is the free fall acceleration on Xenophou
1 answer:
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Answer:
82.1 km
Explanation:
We need to resolve each displacement along two perpendicular directions: the east-west direction (let's label it with x) and the north-south direction (y). Resolving each vector:
Vector B is 48 km south, so:
Finally, vector C:
Now we add the components along each direction:
So, the resultant (which is the distance in a straight line between the starting point and the final point of the motion) is
Complete question
The complete question is shown on the first and second uploaded image
Answer:∈
Answer to first question is shown on the second uploaded image.
Part B the Answer is:
The ratio is evaluated to be 49.99
Explanation:
The explanation is shown on the third ,fourth and fifth image.
