On the planet Xenophous a 1.00 m long pendulum on a clock has a period of 1.32 s. What is the free fall acceleration on Xenophou
1 answer:
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Answer:
19.3m/s
Explanation:
Use third equation of motion
where v is the velocity at halfway, u is the initial velocity, g is gravity (9.81m/s^2) and h is the height at which you'd want to find the velocity
insert values to get answer
Answer:
Explanation:
The magnitude of the electrical force between the two point charges is
where
k is the Coulomb's constant
is the magnitude of each charge
r = 3.00 m is the separation between the two charges
Substituting the numbers into the formula, we find