Boron’s chemistry is not typical of its group.(a) Cite three ways in which boron and its compounds differ significantly from the
1 answer:
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Explanation:
Expression for the speed is as follows.
where, = root mean square speed
k = Boltzmann constant
T = temperature
M = molecular mass
As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of as follows.
=
= 498.5 m/s
Hence, for oxygen atom is 498.5 m/s.
For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its speed as follows.
=
= 524.5 m/s
Therefore, speed for nitrogen is 524.5 m/s.