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Paladinen [302]

3 years ago

13

Which of the following represents a chemical property of hydrogen gas? A) It is gaseous at room temperature. B) It is less dense

than air. C) It reacts explosively with oxygen. D) It is colorless.

1 answer:

ehidna [41]3 years ago

3 0

Answer:

C) It reacts explosively with oxygen.

Explanation:

Physical properties are usually those that can be observed using our senses such as color, luster, freezing point, boiling point, melting point, density, hardness and odor.

What are the Chemical Properties of Hydrogen? They are the characteristics that determine how it will react with other substances or change from one substance to another.

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sweet [91]

Answer:

what I show me a image plz mark me as brainleast

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2 years ago

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The drawing shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel a

Pavel [41]

Answer:

$F=27.39N$

Explanation:

Take sum of torques at the point the step touches the wheel, that eliminates two torques

Σ $T=T_{N}+T_{f}+T_{W}$

Since we are looking for when the wheel just starts to rise up N-> 0 so no torque due to normal force

$T_{N}=0$

The perpendicular lever arm for the F force is R-h

$T_{f}=F*(r-h)$

And the T of gravity according to the image

$T_{W}=W*(\sqrt{r^2-(r-h)^2}$

Σ $T=0$

$T_{N}+T_{f}+T_{W}=0$

$F*(r-h)+W*(\sqrt{r^2-(r-h)^2}=0$

$F=\frac{W*(\sqrt{r^2-(r-h)^2}}{r-h}$

$F=\frac{24.9 N*(\sqrt{0.336^2-(0.336-0.110)^2}}{(0.336-0.11)}$

$F=27.39N$

4 0

2 years ago

A Christmas light is made to flash via the discharge of a capacitor. The effective duration of the flash is 0.25 s (which you ca

Sonbull [250]

Answer:

The correct solution is:

(a) $1.375\times 10^{-2} \ J$

(b) $4.43\times 10^{-3} \ C$

(c) $1.42\times 10^{-3} \ F$

(d) $178.57 \ \Omega$

Explanation:

The given values are:

Effective duration of the flash,

ζ = 0.25 s

Average power,

$P_{avg}=55 \ mW$

$=55\times 10^{-3} \ W$

Average voltage,

$V_{avg}=3.1 \ V$

Now,

(a)

⇒ $E=P_{avg}\times \zeta$

On substituting the values, we get

⇒ $=55\times 10^{-3}\times 0.25$

⇒ $=1.375\times 10^{-2} \ J$

(b)

⇒ $E=Q\times V_{avg}$

then,

⇒ $Q=\frac{E}{V_{avg}}$

On substituting the values, we get

⇒ $=\frac{1.375\times 10^{-2}}{3.1}$

⇒ $=4.43\times 10^{-3} \ C$

(c)

⇒ $C=\frac{Q}{V}$

⇒ $=\frac{4.43\times 10^{-3}}{3.1}$

⇒ $=1.42\times 10^{-3} \ F$

(d)

As we know,

⇒ $R=\frac{1}{4C}$

⇒ $=\frac{1}{4\times 1.42\times 10^{-3}}$

⇒ $=\frac{1000}{5.6}$

⇒ $=178.57 \ \Omega$

5 0

2 years ago

What is the distance from the earth's center to a point outside the earth where the gravitational acceleration due to the earth

Crazy boy [7]

R2^ 2 / R1 ^2 = g1 / g2 = 38

<span>R2 = R1 x √38 = 6.1644* R1 </span>

<span>R2 = 6.1644 x 6378 000 = 39316632.5 m</span>

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3 years ago

Five hundred joules of heat are added to a closed system. The initial internal energy of the system is 87 J, and the final inter

mina [271]

The answer is D. i got all the other ones wrong ._.

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