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Flura [38]
3 years ago
15

Automobile traveling at 65 mph constant on the road described below. Find rate at which radar must rotate when theta = 15 deg. A

ns: theta_dot = 0.219 rad/s.
Physics
1 answer:
Finger [1]3 years ago
3 0

Answer:

The rate at which radar must rotate is 0.335 rad/s.

Explanation:

Given that,

Velocity = 65 m/h = 29.0576 m/s

Angle = 15°

Suppose, the radius given by

r=(100\cos2\theta)\ m

We need to calculate the rate at which radar must rotate

Using formula of linear velocity

v=r\omega

\omega=\dfrac{v}{r}

Where, v = velocity

r = radius

Put the value into the formula

\omega=\dfrac{29.0576}{100\cos30}

\omega=0.335\ rad/s

Hence, The rate at which radar must rotate is 0.335 rad/s.

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Reading or writing on a phone is especially dangerous while driving because:
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Answer:

Explanation:

When we are driving we need a lot of attention and concentration. Also one involved in driving should be consious and courteous

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It will good if use mobile after stopping the vehicle

Thanks

5 0
3 years ago
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What is meant by the statement that a laser beam is coherent, mono-chromatic and parallel?
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Answer:

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8 0
3 years ago
A spring gun consists of a spring inside a plastic tube with spring constant, k. The spring can be compressed 20 cm from its equ
emmainna [20.7K]

Answer: The spring constant is K=392.4N/m

Explanation:

According to hook's law the applied force F will be directly proportional to the extension e produced provided the spring is not distorted

The force F=ke

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e=20cm to meter 20/100= 0.2m

m=100g to kg m=100/1000= 0.1kg

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Ignoring air resistance

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Since the compression causes the plastic ball to poses potential energy hence energy stored in the spring

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5 0
3 years ago
1.)A tank travels at a rate of 10.0 km/hr for 12.00 minutes, then at 15.0 km/hr for 8.00
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12.00 min = 0.2 hr

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(10.0 km/hr + 15.0 km/hr + 20.0 km/hr) / 3

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Change in position:

(10.0 km/hr) (0.2 hr) + (15.0 km/hr) (0.15 hr) - (20.0 km/hr) (0.2 hr)

= 0.25 km

Average velocity:

(10.0 km/hr + 15.0 km/hr - 20.0 km/hr) / 3

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