O' is the molecule that is associated with oxygen and hydrogen
V = 550 mL = 0.550 L
V = 22.4 L/mol (STP)
M(CO₂)=44.01 g/mol
n(CO₂)=v/V
m(CO₂)=n(CO₂)M(CO₂)=vM(CO₂)/V
m(CO₂)=0.550*44.01/22.4=1.08 g
Make sure all units are consistent. Convert ml to L first. (500ml = 0.5L). Then divide the mole by the volume which would result to 1.6*10^-4mol/L. This can also be expressed as interms of molarity (M). 1 M = 1 mol/L hence the final answer is <span>1.6*10^-4 M. </span>
Answer:
o increase the rate of chemical reaction
Explanation:
Enzymes are chemical catalysts that speed up chemical reactions by lowering their activation energy. Enzymes have an active site with a unique chemical environment that fits particular chemical reactants for that enzyme, called substrates. Enzymes and substrates are thought to bind according to an induced-fit model.
Answer:
FALSE
Explanation:
Assuming that the gas is ideal
Therefore the gas obeys the ideal gas equation
<h3>Ideal gas equation is </h3><h3>P × V = n × R × T</h3>
where
P is the pressure exerted by the gas
V is the volume occupied by the gas
n is the number of moles of the gas
R is the ideal gas constant
T is the temperature of the gas
Here volume of the gas will be the volume of the container
Given the volume of the container and number of moles of the gas are constant
As R will also be constant, the pressure of the gas will be directly proportional to the temperature of the gas
P ∝ T
∴ Pressure will be directly proportional to the temperature
