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ladessa [460]
3 years ago
10

A concave mirror has a radius of curvature of 10 cm. Find the location an height of the image if the distance of the object is 8

cm and the height of the object is 1.5 cm, using a scaled ray diagram
Physics
1 answer:
puteri [66]3 years ago
7 0
R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3

HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
HEIGHT OF IMAGE=40/3*1/-8*15/10
                              =-20/8
                              =-2.5
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A runner is jogging in a straight line at a
Fiesta28 [93]

Answer:

Total distance traveled by bird is 10.5 km.

Explanation:

Given that,

Velocity of runner= 8.4 km/hr

Distance = 6.3 km

Velocity of bird = 42 km/hr

Suppose, How far does the bird travel?

We need to calculate the time of bird

Using formula of time

t=\dfrac{d}{v_{b}}

Put the value into the formula

t=\dfrac{6.3}{42}

t=0.15\ hr

We need to calculate the distance runner travels during time period

Using formula of distance

d=v_{r}\times t

d=8.4\times0.15

d=1.26\ km

We need to calculate the distance of runner to FL

Using distance

d'=6.3-1.26

d'=5.04\ km

We need to calculate the net closing speed between runner and bird

Using speed

v'=v_{r}+v_{b}

v'=8.4+42

v'=50.4\ km/hr

We need to calculate the time for runner and bird to meet

Using formula of time

t=\dfrac{d}{v'}

Put the value into the formula

t=\dfrac{5.04}{50.4}

t=0.1\ hr

We need to calculate the distance covered by runner

Using formula of distance

d=vt

Put the value into the formula

d=8.4\times0.1

d=0.84\ km

We need to calculate the distance covered by bird to runner

Using formula of distance

d=vt

Put the value into the formula

d=42\times0.1

d=4.2\ km

We need to calculate the total distance

Using distance

D=6.3+4.2

D=10.5\ km  

Hence, Total distance traveled by bird is 10.5 km.

4 0
3 years ago
A p-wave arrives at 3:00:00 and the s-wave arrives at 3:07:20, what is the exact distance that the seismic station is away from
maxonik [38]

The exact distance from the seismic station to the epicenter is 6000 km.

<h3>Epicenter of earthquake</h3>

The earthquake's epicenter is the point above the fault location on the earth's surface.

Given that:

A p-wave arrives at 3:00:00 and the s-wave arrives at 3:07:20.

Difference in arrival time = 3:07:20 - 3:00:00 = 7 minutes 20 seconds

From the earthquake time travel graph, a time difference of 7 min 20 sec is at x = 6

The exact distance from the seismic station to the epicenter is 6000 km.

Find out more on Epicenter of earthquake at: brainly.com/question/1969968

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