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ladessa [460]
3 years ago
10

A concave mirror has a radius of curvature of 10 cm. Find the location an height of the image if the distance of the object is 8

cm and the height of the object is 1.5 cm, using a scaled ray diagram
Physics
1 answer:
puteri [66]3 years ago
7 0
R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3

HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
HEIGHT OF IMAGE=40/3*1/-8*15/10
                              =-20/8
                              =-2.5
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Answer:

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Explanation:

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E = Energy of Photon = ?

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Therefore,

E = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(4 x 10⁻⁷ m)

E = (4.97 x 10⁻¹⁹ J)(1 eV/1.6 x 10⁻¹⁹ J)

E = 3.1 eV

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Binding Energy = E - Kinetic Energy

Binding Energy = 3.1 eV - 0.86 eV

<u>Binding Energy = 2.24 eV</u>

4 0
3 years ago
A ray of light is incident on a flat surface of a block of polystyrene, with an index of refraction of 1.49, that is submerged i
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Answer:

21.5°

Explanation:

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Using Snell's law

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4 0
3 years ago
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ahrayia [7]

Answer:

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Explanation:

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Answer:

0.256 hours

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