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Anna35 [415]
3 years ago
10

Suppose the Earth's magnetic field at the equator has magnitude 0.00005 T and a northerly direction at all points. How fast must

a singly ionized uranium atom (m=238u, q=e) move so as to circle the Earth 1.44 km above the equator? Give your answer in meters/second.
Physics
1 answer:
sasho [114]3 years ago
5 0

Answer:

Velocity will be v=1.291\times 10^8m/sec

Explanation:

We have given magnetic field B = 0.00005 T

Mass m = 238 U

We know that 1u=1.66\times 10^{-27}kg

So 238 U =238\times 1.66\times 10^{-27}=395.08\times 10^{-27}kg

Radius =R+1.44=6378+1.44=6379.44KM

We know that magnetic force is given by

F=qvB which is equal to the centripetal force

So qvB=\frac{mv^2}{r}

1.6\times 10^{-19}\times v\times 0.00005=\frac{395.08\times 10^{-27}v^2}{6379.44}

v=1.291\times 10^8m/sec

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const2013 [10]

Answer:

The Forces of Flight

At any given time, there are four forces acting upon an aircraft.  

These forces are lift, weight (or gravity), drag and thrust. Lift is  

the key aerodynamic force that keeps objects in the air. It is the  

force that opposes weight; thus, lift helps to keep an aircraft in  

the air. Weight is the force that works vertically by pulling all  

objects, including aircraft, toward the center of the Earth. In order  

to fly an aircraft, something (lift) needs to press it in the opposite  

direction of gravity. The weight of an object controls how strong  

the pressure (lift) will need to be. Lift is that pressure. Drag is a  

mechanical force generated by the interaction and contract of a  

solid body, such as an airplane, with a fluid (liquid or gas). Finally,  

the thrust is the force that is generated by the engines of an  

aircraft in order for the aircraft to move forward.

Explanation:

5 0
3 years ago
A rock with a mass of 540 g in air is found to have an apparent mass of 342 g when submerged in water. (a) What mass of water is
AleksandrR [38]

(a) 198 g

When the rock is submerged into the water, there are two forces acting on the rock:

- its weight, equal to W=mg (m=mass, g=acceleration of gravity), downward

- the buoyant force, equal to B=m_w g (m_w=mass of water displaced), upward

So the resultant force, which is the apparent weight of the rock (W'), is

W'=W-B

which can be rewritten as

m'g = mg-m_w g

where m' is the apparent mass of the rock. Using:

m = 540 g

m' = 342 g

we find the mass of water displaced

m_w = m-m'=540 g-342 g=198 g

(b) 1.98\cdot 10^{-4} m^3

If the rock is completely submerged, the volume of the rock corresponds to the volume of water  displaced.

The volume of water displaced is given by

V_w = \frac{m_w}{\rho_w}

where

m_w = 198 g = 0.198 kg is the mass of the water displaced

\rho_w = 1000 kg/m^3 is the density of the water

Substituting,

V_w = \frac{0.198}{1000}=1.98\cdot 10^{-4} m^3

And so this is also the volume of the rock.

(c) 2727 kg/m^3

The average density of the rock is given by

\rho = \frac{m}{V}

where

m = 540 g = 0.540 kg is the mass of the rock

V=1.98\cdot 10^{-4} m^3 is its volume

Substituting into the equation, we find

\rho = \frac{0.540 kg}{1.98\cdot 10^{-4}}=2727 kg/m^3

3 0
3 years ago
An object is five focal lengths from a concave mirror.how do the object and image heights compare?
enot [183]

An object distance is presented as s = 5f and we know that the mirror equation relates the image distance to the object distance and the focal length.

The mirror equation is 1/f = 1/s + 1/s’ where the variable f stands for the focal length of the mirror. Variable (s) represents the distance between the mirror surface and the object and the variable <span>(s’) represents the distance between the mirror surface and the image. </span>

In addition, a concave mirror will have a positive focal length (f) and a convex mirror will have a negative focal length (f).

Now, we then have 1/f = 1/5f + 1/s’ which is s’ = 5f/4

Then we get the magnification ratio that expresses the size or amount of magnification or reduction of the object or image and to get the magnification, we use this equation: M= s’/s

M= 5f/4x5f

s’ = 1/4s

Therefore, the image height is one fourth of the object height

7 0
3 years ago
HEELLPPPP All of the following are major parts of the earth's interior except? core asthenosphere stratosphere mantle
Luden [163]
<span>1. 10x
2. fault line
3. UV Waves
4. through solids and liquids
5. inner core
6. low temperature
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15. Lithospheric plates
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7 0
3 years ago
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A wave has a frequency of 46 Hz and a wavelength of 1.7 meters. What is the speed of the wave?
olga55 [171]

Answer:0.588..

Explanation:

7 0
3 years ago
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