Explanation:
The given data is as follows.
mass, m = 75 g
Specific heat of water = 4.18
First, we will calculate the heat required for water is as follows.
q = 
= 
= 8464.5 J/mol
= 8.46 kJ ......... (1)
Also, it is given that 
= (20 + 273) K = 293 K and specific heat of ice is 2.108 kJ/kg K.
Now, we will calculate the heat of fusion as follows.
q = 
= 
= -46.32 kJ ......... (2)
Now, adding both equations (1) and (2) as follows.
8.46 kJ - 46.32 kJ
= -37.86 kJ
Therefore, we can conclude that energy in the form of heat (in kJ) required to change 75.0 g of liquid water at 
to ice at 
is -37.86 kJ.
laser in the garage . . . D
wavelength of a sound . . . C
how sound travels . . . B
electromagnetic spectrum . . . D
Answer:
V=11.74m/s, 69.59°
Explanation:
From newtons equation of motion ,we know that
V^2 = u^2+2gh
for the rt
For the vertical component of the speed
Vy^2=V0^2+ 2gh
Vy= the final speed in the vertical axis
V0= initial speed, 0m/s
g= acceleration due to gravity 9.81m/s
h=height/distance between the eagle and the lake
Vy^2= 2*9.81*6.2
Vy =√121.644
Vy=11.02m/s
The resultant speed will be
V=(Vy^2+Vx^2)^0.5
V=(11.02^2+4.1^2)^0.5
V=137.7241^0.5
V=11.74m/s
Direction
Tan^-1(11.02/4.1)
β=69.59°
V=11.74m/s, 69.59°
Answer =11.74m/s, b°
Hello! Your answer would be D. Interference
This is because interference causes vibration!!!
Answer:
Bulb 1 has more resistance.
Explanation:
Given that,
Two lightbulbs work on a 120-V circuit.
The power of circuit 1, P₁ = 50 W
The power of circuit 2, P₂ = 100 W
We need to find the bulb that has a higher resistance.
The power of the bulb is given by :
For bulb 1,
For bulb 2,
So, bulb 1 has higher resistance.
