Answer:
The horizontal component of the velocity is 188 m/s
The vertical component of the velocity is 50 m/s.
Explanation:
Hi there!
Please, see the figure for a graphic description of the problem. Notice that the x-component of the vector velocity (vx), the y-component (vy) and the vector velocity form a right triangle. Then, we can use trigonometry to obtain the magnitude of vx and vy:
We can find vx using the following trigonometric rule of a right triangle:
cos α = adjacent / hypotenuse
cos 15° = vx / 195 m/s
195 m/s · cos 15° = vx
vx = 188 m/s
The horizontal component of the velocity is 188 m/s
To calculate the y-component we will use the following trigonometric rule:
sin α = opposite / hypotenuse
sin 15° = vy / 195 m/s
195 m/s · sin 15° = vy
vy = 50 m/s
The vertical component of the velocity is 50 m/s.
Answer:
B electrons protons and neutrons
hope i helped...
Explanation:
The glowing beam was repelled by a negatively charged plate because they were negatively charged
<h3>What are the nature of charges?</h3>
The nature of charges refers to the properties of charges.
There are two types of charges:
- negative charges
- positive charges
The law of electricity states that opposite charges attract whereas like charges repel.
Therefor, in Thomson’s experiment, the glowing beam was repelled by a negatively charged plate because they were negatively charged
In conclusion, like charges repel while opposite charges attract.
Learn more about charges at: brainly.com/question/12781208
#SPJ1
A perfectly elastic<span> collision is defined as one in which there is no loss of </span>kinetic energy<span> in the collision. Therefore, we just add the kinetic energies of each system. We calculate as follows:
KE = 0.5(</span>1.0 × 10^3)(12.5 )^2 + 0.5(1.0 × 10^3)(12.5 )^2
KE = 156250 J = 1.6 x 10^5 J -------> OPTION A
In rooms where there are multiple lights, a parallel circuit is better.
In a series circuit, if one light broke, all of the lights would turn off, as the circuit would be broken.
However, in parallel, if one bulb broke, the circuit could still be complete through the other bulbs, so they will stay on.
