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3 years ago

13

when an object is charged by contact, what kind of charge does the object have compared with the charge on the on the object giv

ing the charge?

1 answer:

sveta [45]3 years ago

5 0

Answer:

the charge that is given by the object is positive charge and the object which is taking the charge is negetively charged

Explanation:

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Why was the microscope and its improvement an important part of the development of the cell theory?

netineya [11]

Answer:it’s is part of the cell theory because they where studying cells and to see it you need a microscope

Explanation:basically in the answer area

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2 years ago

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If the car went 30 km west in 25 min. and then 40 km south in 35 min., what would be its average speed?

Alika [10]

The total distance is 70km.
The total time is 60 minutes or 1 hour.
Speed=Distance÷Time
=70÷1
=70km/h

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2 years ago

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The work energy principle states that the change in kinetic energy of an object is equal to the net work done on the object. If

sattari [20]

Answer:

$v=\sqrt{2gh}\ m/s$

Explanation:

From work energy theorem

Work done by all forces = Change in kinetic energy

Lets take

m= mass of object

h=height from the ground surface

initial velocity of object = 0 m/s

The final velocity of object is v

Work done by gravitational force = m g . h

The final kinetic energy = 1/2 m v²

So

Work done by all forces = Change in kinetic energy

m g h = 1/2 m v² - 0

v² = 2 g h

$v=\sqrt{2gh}\ m/s$

6 0

3 years ago

A train has a final velocity of 110 km/h. It accelerated for 36 s at 0.50 m/s2 . What was its initial velocity

Tems11 [23]

The initial velocity of the train is 12.56 m/s.

<h3>Initial velocity</h3>

The initial velocity of the train can be determined by using the first kinematic equation as shown below;

v = u + at

u = v - at

where;

v is the final velocity = 110 km/h = 30.56 m/s
u is the initial velocity

u = 30.56 - (36 x 0.5)

u = 12.56 m/s

Thus, the initial velocity of the train is 12.56 m/s.

Learn more about initial velocity here: brainly.com/question/19365526

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2 years ago

70-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 844 N. What is the acceleration o

mario62 [17]

Answer : The acceleration of the elevator is, $2.25m/s^2$

Explanation :

Formula used to calculate the acceleration of the elevator is:

$F=mg+ma\\\\ma=F-mg\\\\a=\frac{F-mg}{m}$

where,

F = force = 844 M

m = mass of man = 70 kg

g = acceleration due to gravity = $9.8m/s^2$

a = acceleration of the elevator = ?

Now put all the given values in the above formula, we get:

$a=\frac{F-mg}{m}$

$a=\frac{844N-(70kg\times 9.8m/s^2)}{70kg}$

$a=2.25m/s^2$

Thus, the acceleration of the elevator is, $2.25m/s^2$

4 0

2 years ago