Uranium-232 has a half-life of 68.8 years. After 344.0 years, how much uranium-232 will remain from a 375.0-g sample?
1 answer:
Uranium-232 will remain 11.72 g
<h3>Further explanation </h3>The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t 1/2 = half-life = 68.8 years
T = duration of decay = 344 years
No= initial sample = 375 g
Uranium-232 remain :
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Answer:
Anion Gained 3 18
Cation Lost 2 36
Cation Lost 3 23
Explanation:
Looking at the ionic notation, the negative symbol (-) indicates that there are more electrons than protons and the positive symbol (+) indicates that there are more protons than electrons.
The number tells you how many was gained or lost.
To determine how many electrons are left, you base this off how many protons there are. The number of protons in an atom is expressed by the atomic number. In a stable atom, you have an equal number of protons and electrons.
Ions occur when electrons are gained or lost.
A cation is positively charged because it LOST an electron. Since there are more protons than electrons, the charge would be positive.
An anion is negatively charged because it gained an electron. Since there are more electrons than protons, the charge would be negative.
Using the explanation above, you can see how the answers were obtained. As for the last column, just use basic math to do this.
The atomic number of Phosphorus (P) is 15, so this means that there are 15 protons. Since it gained 3 electrons, just add 3 to 15:
15 + 3 = 18
Sr has an atomic number 38. Since it lost 2 electrons, just subtract 2 from the atomic number.
38-2 = 36
Fe has an atomic number 26. It lost 3 electrons, so we subtract again.
26-3 = 23
The lithium ion[Li⁺]=1.642 M
<h3>Further explanation</h3>Ionic compounds will dissociate into ions when dissolved in water. The strength of the dissociation depends on the strength of the electrolyte properties. The stronger it is, the more ions will dissociate
Reaction
Li₂S⇒2Li⁺+S²⁻
mol ratio Li₂S : Li⁺: S²⁻ = 1 : 2 : 1
so the lithium-ion (Li⁺) concentration :