Answer : The moles of are, 0.1187, 0.2374 and 0.0313 moles respectively.
Explanation : Given,
Initial moles of = 0.15 mole
Initial moles of = 0.3 mole
Moles of at equilibrium = 0.1187 mole
The given equilibrium reaction is,
Initial moles 0.15 0.3 0
At equilibrium (0.15-x) (0.3-2x) x
As we are given that,
Moles of at equilibrium = 0.1187 mole = 0.15 - x
0.15 - x = 0.1187
x = 0.0313
Moles of at equilibrium = 0.3 - 2x = 0.3 - 2(0.0313) = 0.2374 mole
Moles of at equilibrium = x = 0.0313 mole
Therefore, the moles of are, 0.1187, 0.2374 and 0.0313 moles respectively.
Answer:
It is given in the question that molarity of the sulphuric acid is 2M, the volume of the sulphuric acid is 20 mL, the volume of the solution is 1`L.
B.False
the number of protons in an atom is equal to the atomic number
Answer:
Delta H per mole =55733.3J
Explanation:
volume of solution = 40ml +40ml =80ml
Mass of solution = 80g (since the density is the same as pure water (1.00 g/mL)
Temperature rise = (27-25)oc =2oc.
Heat liberated (Q) = -McT
= 80* 4.18* 2= -668.8J
Number of moles of NaOH in solution = 0.3x 40/1000 =0.012 mole.
Number of moles of HBr in solution =0.3x 40/1000 =0.012 mole.
When 0.012 mole of NaOH reacts with 0.012 mole of HBr, -668.8J was liberated.
Hence. 1 mole of NaOH reacts with 1mole HBr to liberate. =-668.8/0.012 =55733.3J
Given:
At 25 degrees Celcius:
amount of generic salt AB3 = 0.0260 moles
Volume of solvent = 1.0 L water
Set up a balanced chemical equation:
AB3 =========> A3+ + 3B-
0.0260M 0.0260 0.078
Ksp = [A][B]^3
Ksp = 1.23 x 10^-5<span />