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12345 [234]
3 years ago
4

PLS HELP ILL MARK YOU BRAINIEST!!!!

Physics
1 answer:
Elena-2011 [213]3 years ago
6 0
(a) Without air friction, she would achieve a velocity of
V = sqrt(2gH) = 17.15 m/s when entering the water. Instead, it is 14.0 m/s.
(Average force)*(distance) = K.E. loss
= (57/2)[17.15^2 - 14^2] = 2793 J
Average force = 2793/15 = 186 N

(b) [(Friction force)+(buoyancy force)]*(distance below water surface ) = (K.E. when entering water)

[Ff +500]*(2.5 m) = (57/2)(14^2)
Ff + 500 = 2234 N
Ff = 1734 N is the average friction force underwater.
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