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Mumz [18]
4 years ago
5

Which piece of equipment should be used to measure 12 mL of DI water?

Chemistry
1 answer:
irga5000 [103]4 years ago
6 0
100 mL graduated cylinder because the device is more precise.
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Which area is most likely closest to a salt marsh or an estuary?
Archy [21]

Answer:

coastal area with very high tides deep ocean water miles from a river's mouth

Explanation:

Marshes are a type of wetland ecosystem where water covers the ground for long periods of time. Marshes are dominated by herbaceous plants, such as grasses, reeds, and sedges(National Geographic Society).

hope dis help

4 0
2 years ago
A solution
son4ous [18]
D. Has a uniform composition and is only able to be separated by chemical means.
5 0
3 years ago
The gas in an engine cylinder is compressed until it has a volume of 0.045 liter and an absolute pressure of 28 atmospheres. If
Hatshy [7]

7.7 \times 10^{2} \; \text{K}.

<h3>Explanation</h3>

Units of each quantity:

  • <em>P</em> = 28 atm;
  • <em>V</em> = 0.045 L;
  • <em>n</em> = 0.020 mol;

Ideal gas constant:

R = 0.0820573 \;\text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}.

Apply the ideal gas law:

T = \dfrac{P \cdot V}{n \cdot R} = \dfrac{{\bf 28} \; \text{atm} \times {\bf 0.045} \;\text{L} }{{\bf 0.020}\; \text{mol} \times {\bf 0.0820573} \;\text{L} \cdot \text{atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}} = {\bf 767.76} \; \text{K}.

All data given in this question come with two significant figures. Round the value of <em>T</em> to two significant figures:

T = 767.76 \;\text{K} = 7.7 \times 10^{2} \; \text{K}.

7 0
3 years ago
Read 2 more answers
Helpp! is Au an element, compound, or mixture?
Stels [109]

Answer:

It's an element.

Explanation:

Au is gold. An "element " on the periodic table. Trust me. Im 100% sure.

7 0
3 years ago
Read 2 more answers
Water flows over Niagara Falls at the average rate of 2,400,000 kg/s, and the average height of the falls is about 50 m. Knowing
Zinaida [17]

Answer:

1) The power of Niagara Falls is 1.176 × 10⁹ W

2) The number of 15 W LED light bulbs it could power is 78.4 × 10⁶ light bulbs

Explanation:

1) The Niagara falls water mass flow rate = 2,400,000 kg/s

The height of the fall = 50 meters

The gravitational potential energy = Mass (kg) × height (m) × gravity (9.8 m/s²)

The power = The energy converted per second = Mass flow rate (kg/s) × height (m) × gravity (9.8 m/s²)

Therefore;

The power of Niagara Falls= 2,400,000 kg/s × 50 m ×9.8 m/s²= 1.176 × 10⁹ W

The power of Niagara Falls = 1.176 × 10⁹ W

2) The number, n, of 15 W LED light bulbs it could power is given by the relation;

n × 15 W = 1.176 × 10⁹ W

∴ n = 1.176 × 10⁹ W/(15 W) = 78.4 × 10⁶ light bulbs

The number of 15 W LED light bulbs it could power = 78.4 × 10⁶ light bulbs.

6 0
4 years ago
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