Answer:
The ball would have landed 3.31m farther if the downward angle were 6.0° instead.
Explanation:
In order to solve this problem we must first start by doing a drawing that will represent the situation. (See picture attached).
We can see in the picture that the least the angle the farther the ball will go. So we need to find the A and B position to determine how farther the second shot would go. Let's start with point A.
So, first we need to determine the components of the velocity of the ball, like this:
we pick the positive one, so it takes 0.317s for the ball to hit on point A.
so now we can find the distance from the net to point A with this time. We can find it like this:
Once we found the distance between the net and point A, we can similarly find the distance between the net and point B:
t= -0.9159s or t=0.468s
we pick the positive one, so it takes 0.468s for the ball to hit on point B.
so now we can find the distance from the net to point B with this time. We can find it like this:
So once we got the two distances we can now find the difference between them:
so the ball would have landed 3.31m farther if the downward angle were 6.0° instead.
G is the answer for apex vs / Chehhhh
Answer:
A lens placed in a transparent liquid becomes invisible because when refractive index of the material of the lens is equal to the refractive index of the liquid in which lens is placed under this condition no bending of light takes place when it travels from liquid to the lens, so both will start behaving like both are same things.
Explanation:
hope it helps :))
Answer:
Ammonia, 
Explanation:
If a Rac variant, in which the residue at position 61 was replaced with an alanine (Rac-61A), was synthesized. Also, Wild-type Rac and Rac-61A were incubated separately with VopC.
In order to obtain data to support that VopC modifies Rac at residue 61, the samples should be analyzed for the presence of Ammonia (![NH_{3}[\tex]) compound.In chemistry, the Vanadyl Phthalocyanine (VopC) comprises of a catalytic domain that activates host cells GTPase Rac irreversibly, through the deamide side chain of the residue existing at position 61.Also, we know that a deamidation reaction gives off Ammonia, [tex](NH_{3})](https://tex.z-dn.net/?f=NH_%7B3%7D%5B%5Ctex%5D%29%20compound.%3C%2Fp%3E%3Cp%3EIn%20chemistry%2C%20the%20Vanadyl%20Phthalocyanine%20%28VopC%29%20comprises%20of%20a%20catalytic%20domain%20that%20activates%20host%20cells%20GTPase%20Rac%20irreversibly%2C%20through%20the%20deamide%20side%20chain%20of%20the%20residue%20existing%20at%20position%2061.%3C%2Fp%3E%3Cp%3EAlso%2C%20we%20know%20that%20a%20deamidation%20reaction%20gives%20off%20Ammonia%2C%20%5Btex%5D%28NH_%7B3%7D%29)
and as such when ammonia is present in the sample containing Wild-type Rac but not in Rac-61A, this simply proves or provide the data to support that VopC modifies Rac at residue 61.
<em>Additionally, deamidation can be defined as the chemical conversion (hydrolysis) of an amide functional group such as glutamine, asparagine, in a polypeptide to another functional group such as glutamic acid or isoaspartic acid respectively by treating it with a strong acid (deamidate, transamidase). </em>
A force is changing the motion of the bus.
<h3>What is Newton's first law of motion?</h3>
Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that form unless acted upon by an external force.
The applied force on the bus in the form of brakes acts as the external force on the bus.
According to Newton's first law of motion, the external force (brakes) will change the motion of the bus.
Thus, we can conclude that a force is changing the motion of the bus.
Learn more about Newton's first law of motion here: brainly.com/question/24922261
