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puteri [66]
3 years ago
8

A basketball referee tosses the ball straight up for the starting tip-off. At what velocity must a basketball player leave the g

round to rise 1.15 m above the floor in an attempt to get the ball
Physics
1 answer:
Anastaziya [24]3 years ago
3 0

Answer:

the basketball player must leave the ground with a velocity of 4.748 m/s

Explanation:

Given that data in the question;

From the third equation of motion;

v² - u² = 2as

such that;

u² = v² - 2as

where u is the initial velocity, v is the final velocity, s is the displacement and a is acceleration

so initial velocity of the basket ball player will be;

u = √( v² - 2as )

so from the question; s is 1.15 m and a = - 9.8 m/s² { player is under negative acceleration to get to the ball } and final velocity of the player will be 0.

so we substitute

u = √( (0)² - (2 × -9.8 × 1.15 )

u = √ -( - 22.54 )

u = √ ( 22.54 )

u = 4.748 m/s

Therefore, the basketball player must leave the ground with a velocity of 4.748 m/s

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Define suspension and list two examples.
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3 0
3 years ago
A mother pushes a baby stroller 10 meters by applying 40 newtons of force. How much work was done?
MA_775_DIABLO [31]
It would be 400 newton joule's! :) hope this helps! the equation is 10m*40n = 400newton!
4 0
3 years ago
Read 2 more answers
A car enters a freeway with a speed of 6.5 m/s and accelerates to a speed of 24 m/s in 3.5 min. How far does the car travel whil
Vesna [10]

Explanation:

<u>Using Equations of Motion</u> :

(1) v = u + at

24 = 6.5 + a * 210

<u>a (Acceleration) = 0.083 m/s^2 </u>

<u>(</u><u>2</u><u>)</u><u> </u> v^2 = u^2 + 2aS

S = 576 - 42.25 / 0.166

<u>S (Distance travelled) = 3215.3 m </u>

(Option A seems a typo since the answer is 3215.3 m)

4 0
3 years ago
Starting from rest, a 4.0-kg body reaches a speed of 8.0 m/a in 20 s. What is te net force acting on the body?
Strike441 [17]
The guy below is wrong!


F=ma
Where force = mass x acceleration

We dont have acceleration, a= change in velocity divided by the time taken.
a = v (final velocity) - u (initial) / t
a us 8-0 (at rest means u was 0) / 20 = 0.4

Using F=ma

F= mass x acceleration 
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F=1.6 N
5 0
3 years ago
a person brings his face close to a mirror . h e finds that the image of his face is magnified write the name of the mirror used
DIA [1.3K]

Answer:

Spherical concave mirrors

Explanation:

Like spherical convex mirrors, spherical concave mirrors have a focus. If the object is closer to the mirror than the focal point is, the image will be virtual, like we talked about before for the plane mirror and the convex mirror.

Concave mirrors, on the other hand, can have real images. If the object is further away from the mirror than the focal point, the image will be upside-down and real---meaning that the image appears on the same side of the mirror as the object.

The closer the object comes to the focal point (without passing it), the bigger the image will be.

You can try this yourself by looking into the concave side of a shiny spoon. If you look into the spoon while holding it at arm’s length, you’ll see an extremely magnified, upside-down image of your face. But as you bring the spoon closer to your eyes, the image will get bigger and bigger.

<em>- Hope this helps! <3</em>

5 0
3 years ago
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