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puteri [66]
3 years ago
8

A basketball referee tosses the ball straight up for the starting tip-off. At what velocity must a basketball player leave the g

round to rise 1.15 m above the floor in an attempt to get the ball
Physics
1 answer:
Anastaziya [24]3 years ago
3 0

Answer:

the basketball player must leave the ground with a velocity of 4.748 m/s

Explanation:

Given that data in the question;

From the third equation of motion;

v² - u² = 2as

such that;

u² = v² - 2as

where u is the initial velocity, v is the final velocity, s is the displacement and a is acceleration

so initial velocity of the basket ball player will be;

u = √( v² - 2as )

so from the question; s is 1.15 m and a = - 9.8 m/s² { player is under negative acceleration to get to the ball } and final velocity of the player will be 0.

so we substitute

u = √( (0)² - (2 × -9.8 × 1.15 )

u = √ -( - 22.54 )

u = √ ( 22.54 )

u = 4.748 m/s

Therefore, the basketball player must leave the ground with a velocity of 4.748 m/s

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jasenka [17]

Weight of the carriage =(m+M)g =142.1\ N

Normal force =Fsin(\theta) + W = 197.1\ N

Frictional force =\mu N=27.59\ N

Acceleration =4.66\ m\ s^{-2}

Explanation:

We have to look into the FBD of the carriage.

Horizontal forces and Vertical forces separately.

To calculate Weight we know that both the mass of the baby and the carriage will be added.

  • So Weight(W) =(m+M)\times g =(9.5+5)\ kg \times 9.8 =142.1\ Newton\ (N)

To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with F_x, force of 110\ N acting vertically downward.Both are downward and Normal is upward so Normal force =Summation\ of\ both\ forces

  • Normal force (N) = Fsin(\theta)+W=110sin(30) + 142.1 =197.1\ N
  • Frictional force (f) =\mu N=0.14\times 197.1 =27.59\ N

To calculate acceleration we will use Newtons second law.

That is Force is product of mass and acceleration.

We can see in the diagram that F_y=Horizontal and F_x=Vertical component of forces.

So Fnet = Fy(Horizontal) - f(friction) = m\times a

  • Acceleration (a) =\frac{Fcos(\theta)-\mu N}{mass(m)} =\frac{(95.26-27.59)}{14.5}= 4.66\ m\ s{^2 }

So we have the weight of the carriage, normal force,frictional force and acceleration.

3 0
2 years ago
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USPshnik [31]

Answer:

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Explanation:

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A truck loaded with sand accelerates along a highway. The driving force on the truck remains constant. What happens to the accel
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Answer:

Acceleration will increase.

Explanation:

The relation between force, mass and acceleration according to the Newton's second law of motion is given as:

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We are given that the driving force on the truck remains constant, so F is constant here. We can rewrite the above equation as:

a=\frac{F}{m}

Since, F is constant, the acceleration of the truck is inversely proportional to the mass.

There is a hole at the bottom of the truck through which the sand is being lost at a constant rate. Since, the sand is being lost, the overall mass of the truck is being reduced.

Since, the acceleration of the truck is inversely proportional to the mass, the reduced mass will result in an increased acceleration.

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When two or more different capacitors are connected in series across a potential source, which of the following statement must b
vova2212 [387]

Answer:

C. Each capacitor carries the same amount of charge.

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When two or more different capacitors are connected in series across a potential source, each capacitor carries the same amount of charge.

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