Equation: M1V1 = M2V2
Where M = concentration & V = volume
Step 1: Write down what is given and what you are trying to find
Given: M1 = 6.00M, V1 = 2.49mL, and V2 = 50.0mL
Find: M2
Step 2: Plug in the values into the equation
M1V1 = M2V2
(6.00M)(2.49mL) = (M2)(50.0mL)
Step 3: Isolate the variable (Divide both sides by 50.0mL so M2 is by itself)
(6.00M)(2.49mL) / (50.0mL) = M2
Answer: M2 = 0.30M
*Don't forget sig figs & units!
For what? what is your question
Answer:
The element with electronic configuartion 1s² and atomic number 3 must be an cation.
Explanation:
The "Z" shows the atomic number. Z stand for zahl. It Is German word and meaning is " number".
In given question Z is equal to three which means an element with atomic number three.
Let consider the X is an element with atomic number three having electronic configuration 1s², but according to this atomic number there should be one more electron present is 2s. If X has the electronic configuration 1s² it means that it lose one electron and X is present in the form of cation.
X⁺ = 1s²
Answer is 0.7 g
Reason: Given: mass of Fe = 5.60 gWe know that, half life of Fe-53 = t1/2 (Fe-53) = 8.51 min.
Thus, after 25.53 mins, number of half life passed = 25.53/8.51= 3
Now, Amount left after first half life = 5.60g/2 = 2.80 g
Amount left after second half life = 2.80g/2 = 1.40 g
Amount left after third half-life = 1.40g/2 = 0.7g.
