Answer:
the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake
Explanation:
This problem can be solved using the kinematics relations, let's start by finding the final velocity of the acceleration period
v² = v₀² + 2 a₁ x
indicate that the initial velocity is zero
v² = 2 a₁ x
let's calculate
v =
v = 143.666 m / s
now for the second interval let's find the distance it takes to stop
v₂² = v² - 2 a₂ x₂
in this part the final velocity is zero (v₂ = 0)
0 = v² - 2 a₂ x₂
x₂ = v² / 2a₂
let's calculate
x₂ =
x₂ = 573 m
as the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake
Answer:
to locate places on earth
Answer:
![W=\frac{773}{4.45}=173.76 l b f](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B773%7D%7B4.45%7D%3D173.76%20l%20b%20f)
Explanation:
![W=\frac{G \cdot m_{e} \cdot m}{(R+h)^{2}}](https://tex.z-dn.net/?f=W%3D%5Cfrac%7BG%20%5Ccdot%20m_%7Be%7D%20%5Ccdot%20m%7D%7B%28R%2Bh%29%5E%7B2%7D%7D)
The law of gravitation
![G=6.673\left(10^{-11}\right) m^{3} /\left(k g \cdot s^{2}\right)](https://tex.z-dn.net/?f=G%3D6.673%5Cleft%2810%5E%7B-11%7D%5Cright%29%20m%5E%7B3%7D%20%2F%5Cleft%28k%20g%20%5Ccdot%20s%5E%7B2%7D%5Cright%29)
Universal gravitational constant [S.I. units]
![m_{e}=5.976\left(10^{24}\right) k g](https://tex.z-dn.net/?f=m_%7Be%7D%3D5.976%5Cleft%2810%5E%7B24%7D%5Cright%29%20k%20g)
Mass of Earth [S.I. units]
![m=89 kg](https://tex.z-dn.net/?f=m%3D89%20kg)
Mass of a man in a spacecraft [S.I. units]
![R=6371 \mathrm{~km}](https://tex.z-dn.net/?f=R%3D6371%20%5Cmathrm%7B~km%7D)
Earth radius [km]
Distance between man and the earth's surface
![h=261 \mathrm{~km} \quad[\mathrm{~km}]](https://tex.z-dn.net/?f=h%3D261%20%5Cmathrm%7B~km%7D%20%5Cquad%5B%5Cmathrm%7B~km%7D%5D)
ESULT ![W=\frac{6.673\left(10^{-11}\right) \cdot 5.976\left(10^{24}\right) \cdot 89}{\left(6371 \cdot 10^{3}+261 \cdot 10^{3}\right)^{2}}=773.22 \mathrm{~N}](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B6.673%5Cleft%2810%5E%7B-11%7D%5Cright%29%20%5Ccdot%205.976%5Cleft%2810%5E%7B24%7D%5Cright%29%20%5Ccdot%2089%7D%7B%5Cleft%286371%20%5Ccdot%2010%5E%7B3%7D%2B261%20%5Ccdot%2010%5E%7B3%7D%5Cright%29%5E%7B2%7D%7D%3D773.22%20%5Cmathrm%7B~N%7D)
![W=\frac{773}{4.45}=173.76 l b f](https://tex.z-dn.net/?f=W%3D%5Cfrac%7B773%7D%7B4.45%7D%3D173.76%20l%20b%20f)
I would say the answer is Pangaea. I got this answer but google searching "all land" means what... and the 3rd or 4th one down it says Answers.com
But i worn you answers.com is a very slow sight...
Hope it helps
and please mark me as brainiest