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AleksAgata [21]
2 years ago
12

A gas is contained in a cylinder with a frictionless moveable piston at a pressure of 3.50 × 105 pascals and a volume of 0.02 cu

bic meters. What is the work done by the gaseous system if the volume is increased to 0.15 cubic meters?
Physics
1 answer:
Softa [21]2 years ago
3 0

W=PΔV

W=3.5 x 10⁵ x (0.15-0.02)

W=4.55 x 10⁴ J

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A textbook of mass 2.02 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose d
Anika [276]

Answer:

a. 7.38 N b. 40.87 N c. 0.113 kg-m²

Explanation:

7 0
4 years ago
A rotating viscometer consists of two concentric cylinders –an inner cylinder of radius Rirotating at angular velocity (rotation
RSB [31]

Answer:

b)  the result we got can be termed approximation because we are neglecting the shear stress acting on the two ends of the cylinder. Here we have considered only the share stress acting on the curved surface area only.

Explanation:

check attachment for solution to A

4 0
3 years ago
A hiker climbs a mountain. Starting at the base of the mountain, he first moved up 520m at a 32.0 degree angle. What is the fina
balu736 [363]

Answer:

\displaystyle \vec{d}=

Explanation:

<u>Displacement Vector</u>

Suppose an object is located at a position  

\displaystyle P_1(x_1,y_1)

and then moves at another position at

\displaystyle P_2(x_2,y_2)

The displacement vector is directed from the first to the second position and can be found as

\displaystyle \vec{d}=

If the position is given as magnitude-angle data ( z , α), we can compute its rectangular components as

\displaystyle x=z\ cos\alpha

\displaystyle y=z\ sin\alpha

The question describes the situation where the initial point is the base of the mountain, where both components are zero

\displaystyle P_1(0,0)

The final point is given as a 520 m distance and a 32-degree angle, so  

\displaystyle x_2=520\ cos32^o= 440.99\ m

\displaystyle y_2=520\ sin32^o=275.6\ m

The displacement is

\displaystyle \vec{d}=

5 0
3 years ago
At which location could you place the south pole of a bar magnet so that it would be pulled toward the magnet shown?
stepan [7]

Answer:

The north pole.

Explanation:

3 0
4 years ago
In a pool game, the cue ball, which has an initial speed of 3.0 m/s, make an elastic collision with the eight ball, which is ini
zhenek [66]

Explanation:

Given

initial speed(u)=3 m/s

mass of each ball is m

Let the cue ball is moving in x direction initially

In elastic collision Energy and momentum is conserved

Let u be the initial velocity and v_1 , v_2 be the final velocity of 8 ball and cue ball respectively

\frac{mu^2}{2}+0=\frac{mv^2_1}{2}+\frac{mv^2_2}{2}

The angle after which cue ball is deflected is given by

\theta _1=90-40=50^{\circ}

Conserving momentum in x direction

mu=mv_1cos40+mv_2cos50

3=v_1cos40+v_2cos50

Along Y axis

0+0=v_1sin40-v_2sin50

v_1sin40=v_2sin50

substitute the value of v_1

we get v_2=1.912 m/s

v_1=2.27 m/s

5 0
3 years ago
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