Consider the following objects and their locations. Object a 2-kg object 5 cm above the floor Object b 2-kg object 120 cm above
1 answer:
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Answer:
(a). The speed of the first ball after the collision is 1.95 m/s.
(b). The direction of the first ball after the collision is 44.16° due south of east.
Explanation:
Given that,
Velocity of one ball u₁= 2.2i m/s
Velocity of second ball u₂=- 0.80i m/s
Final velocity of the second ball v₂= 1.36j m/s
The mass of the identical balls are
(a). We need to calculate the speed of the first ball after the collision
Using law of conservation of momentum
Along X- axis
Put the value into the formula
Along Y-axis
Put the value into the formula
Then the final speed of the first ball
(b) We need to calculate the direction of the first ball after the collision
Using formula of direction
Negative sign shows the direction of first ball .
Hence, (a). The speed of the first ball after the collision is 1.95 m/s.
(b). The direction of the first ball after the collision is 44.16° due south of east.
Answer:
Explanation:
Calculate the volume of the lead
Now calculate the bouyant force acting on the lead
This force will act in upward direction
Gravitational force on the lead due to its mass will act in downward direction
Hence the difference of this two force
If V is the volume submerged in the water then bouyant force on the bobber is
Equate bouyant force with the tension and gravitational force
Now Total volume of bobble is
=
Answer:
<h2>23.33 kg </h2>Explanation:
The mass of the object can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>23.33 kg</h3>Hope this helps you