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GuDViN [60]
3 years ago
9

Consider the following objects and their locations. Object a 2-kg object 5 cm above the floor Object b 2-kg object 120 cm above

the floor Object c 3-kg object 120 cm above the floor Object d 3-kg object 80 cm above the floor (i) Rank the gravitational accelerations you would measure for the objects. List the one with the largest-magnitude acceleration first. If any are equal, show their equality in your list.
Physics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

The gravitational acceleration is same for all objects.

a = b = c = d

Explanation:

Acceleration due to gravity or gravitational acceleration is the force exerted by Earth on unit mass of an object.

Acceleration due to gravity doesn't depend on the height of the object when the height is object is near to the surface of the Earth. Only when the height is comparable to the radius of the Earth, the value of gravitational acceleration changes.

But for the objects here, the gravitational acceleration is independent of the mass or height of the objects and has a constant value of 9.8 m/s².

Therefore, the gravitational acceleration of all the objects is same.

If 'a', 'b', 'c', and 'd' represent gravitational accelerations of objects 'a', 'b', 'c', and 'd' respectively, then a = b = c = d.

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I believe this is right but double check to make sure :)
7 0
2 years ago
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qwelly [4]

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5 0
3 years ago
A circuit consists of one 330 ohm resistor in series with two other resistors (470 ohms and 220 ohms) connected in parallel. Wha
umka21 [38]

Answer:

power drain on an ideal battery, P = 0.017 W

Given:

R_{1} = 330\ohm

R_{2} = 470\ohm

R_{3} = 220\ohm

Since, R_{2} = 470\ohm and R_{3} = 220\ohm are in parallel and this combination is in series with R_{1} = 330\ohm, so,

Equivalent resistance of the circuit is given by:

R_{eq} = \frac{R_{2}R_{3}}{R_{2} + R_{3}} + R_{1}

R_{eq} = \frac{470\times 220}{470 + 220} + 330

R_{eq} = 149.85 + 330 = 479.85 \ohm

power drain on an ideal battery, P = \frac{V^{2}}{R_{eq}}

                                                      P = \frac{2.9^{2}}{479.85}

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4 0
3 years ago
Consider two identical insulated metal spheres, A and B. Sphere A initially has a charge of -6.0 units and sphere B initially ha
Oksi-84 [34.3K]

Answer:

<em>-2 units of charge</em>

Explanation:

charge on A = Qa = -6 units

charge on B = Qb = 2 units

if the spheres are brought in contact with each other, the resultant charge will be evenly distributed on the spheres when they are finally separated.

charge on each sphere will be = \frac{Qa + Qb}{2}

charge on each sphere =  \frac{-6 + 2}{2} = \frac{-4}{2} = <em>-2 units of charge</em>

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3 years ago
A light ray is incident from air into glass (ng = 1.52) then onto water (nw= 1.33). The wavelength of light in air (na= 1) is ai
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The answer is is b hope this helped
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