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lidiya [134]
3 years ago
5

What happens when aluminum fills its valence shell?

Physics
2 answers:
Digiron [165]3 years ago
7 0

Answer:

Correct answer is B. Three electrons are gained, creating Al ^ -3

Explanation:

Aluminum in its valence shell has 3 electrons, this shell can have a maximun of 6 electrons. Then, to fill its valence shell, 3 electrons must be gained, and then the valence shell would have 6 electrons and would be complete.

If 3 electrons are gained, then Aluminum, would have a charge of -3, since each electron gained gives negative charge to the atom.

Al^ -3  is a ion of aluminum with charge -3.

Juliette [100K]3 years ago
4 0
I beileve the answer is B
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Find the mass of a 52.2N bucket.​
Goshia [24]

Answer:

m = 5.22 kg

Explanation:

The force acting on the bucket is 52.2 N.

We need to find the mass of the bucket.

The force acting on the bucket is given by :

F = mg

g is acceleration due to gravity

m is mass

m=\dfrac{F}{g}\\\\m=\dfrac{52.2}{10}\\\\=5.22\ kg

So, the mass of the bucket is 5.22 kg.

3 0
2 years ago
Select all that apply. There MIGHT be more than one.
Stolb23 [73]
I believe the answer to your question is “Lithosphere plate boundaries”

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Hope this helps!:)
4 0
2 years ago
A horizontal uniform meter stick supported at the 50-cm mark has a mass of 0.50 kg hanging from it at the 20-cm mark and a 0.30
ElenaW [278]

Answer:

70 cm

Explanation:

0.5 kg at 20 cm

0.3 kg at 60 cm

x = Distance of the third 0.6 kg mass

Meter stick hanging at 50 cm

Torque about the support point is given by (torque is conserved)

0.5(50-20)=0.3(60-50)+0.6x\\\Rightarrow x=\dfrac{0.5(50-20)-0.3(60-50)}{0.6}\\\Rightarrow x=20\ cm

The position of the third mass of 0.6 kg is at 20+50 = 70 cm

7 0
3 years ago
Read 2 more answers
A gyroscope flywheel of radius 3.25 cm is accelerated from rest at 11.6 rad/s2 until its angular speed is 1820 rev/min. (a) What
kati45 [8]

Explanation:

The given data is as follows.

           radius (r) = 3.25 cm,    \alpha = 11.6 rad/s^{2}

Now, we will calculate the tangential acceleration as follows.

          a_{tangential} = \alpha \times r

Putting the given values into the above formula as follows.

         a_{tangential} = \alpha \times r

                      = 11.6 rad/s^{2} \times 3.25 cm

                      = 37.7 rad cm/s^{2}

Thus, we can conclude that the tangential acceleration of a point on the rim of the flywheel during this spin-up process is 37.7 rad cm/s^{2}.

6 0
3 years ago
Which element is likely to be the most reactive? bromine (Br) chlorine (Cl) fluorine (F) iodine (I)
RUDIKE [14]

Answer:

Fluorine is the most reactive element

5 0
3 years ago
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