Answer:
range of movement is 1.49 mm
Explanation:
given data
focal length = 45 mm
distance = 1.4 m
distance from the lens = 35 mm
distance from infinity down = 1.4 m =
to find out
range of movement
solution
we will apply here lens equation that is
1/f = 1/p + 1/q
here f = 45 and p = infinity to 1400 mm
we find here image distance that is q
1/45 = 0 + 1/q ......1
q = 45 mm
and
1/45 = 1/1400 + 1/q ......2
q = 46.49
so range of movement
that is 46.49 - 45
range of movement is 1.49 mm
I think the answer is B because I did this before
Answer:
605 J
Explanation:
Efficiency = work out / work in
0.78 = W / 775 J
W = 605 J
<span>The terminal velocity of a sand grain in the air is greater than the terminal velocity of the same sand grain in seawater. The terminal velocity is greater in the air because it is less dense compared to a much denser sea water. Terminal velocity takes lace when an object is constantly free-falling.</span>
