The answer to your question is letter D. Secured.
The temperature rose. so kinetic energy increase. the answer is A. concentration will not affected
Answer:
The number of copper atoms 12.405 ×10²³ atoms.
The number of silver atoms 13.13 ×10²³ atoms.
Beaker B have large number of atoms.
Explanation:
Given data:
In beaker A
Number of moles of copper = 2.06 mol
Number of atoms of copper = ?
In beaker B
Mass of silver = 222 g
Number of atoms of silver = ?
Solution:
For beaker A.
we will solve this problem by using Avogadro number.
The number 6.022×10²³ is called Avogadro number and it is the number of atoms in one mole of substance.
While we have to find the copper atoms in 2.06 moles.
So,
63.546 g = 1 mole = 6.022×10²³ atoms
For 2.06 moles.
2.06 × 6.022×10²³ atoms
The number of copper atoms 12.405 ×10²³ atoms.
For beaker B:
107.87 g = 1 mole = 6.022×10²³ atoms
For 222 g
222 g / 101.87 g/mol = 2.18 moles
2.18 mol × 6.022×10²³ atoms = 13.13 ×10²³ atoms
Answer:
Explanation:
Let's try and figure out the ones you don't keep.
Receipts from the dollar tree. You can't return what you bought and you only paid a dollar. It's not worth it.
Food receipts. You can't return it and unless you want to itemize what you spend / month and on what, they don't serve any purpose.
Now figure out which ones you would want to keep
1. Anything pertaining to medical perscriptions. I don't know how it works in the United States, but in Canada we are allowed to deduct only medications with a DIN number.
2 Anything that you would use for travelling that is not for pleasure (ie it is a business expense). So if you are a salesman and your territory is from A to B you would deduct meals, mileages, motels if you must stay away from home
3 In the states some tax receipts are deductible, so you might want to save those.
Answer:
-3
Explanation:
The oxidation state or oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.
The complex anion here is [Cr(CN)6]3-.
Now, as the oxidation state of CN or cyanide ligand is -1, and if we suppose the oxidation state of Cr to be 'x', then; x - 6 = -3 (overall charge on the anion),
so x= +3. Hence the oxidation state of Chromium in this complex hexacyanochromium (III) anion comes out to be -3.
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