The balanced chemical reaction will be:
H2 + Cl2 = 2HCl
We are given the amount of reactants and since chlorine is in excess we can say that all of the hydrogen supplied will be in complete reaction. This will be our starting point.
0.8 g H2 (1 mol H2 / 2.02 gH2) (2 mol HCl/1mol H2) ( 36.46 g HCl/1mol HCl) = 28.88 g HCl
Thus, the answer is 28.88g H2O.
The question is incomplete, the complete question is;
The lightest particle among the following is:
• Electron •Proton • Neutron • Alpha
Answer:
Electron
Explanation:
There three basic subatomic particles are electrons, protons and neutrons. Both protons and neutrons are found in the nuclear and both contribute towards the mass of the atom. The alpha particle has the same mass as the helium nucleus.
However, the electrons are found in orbiit and have a negligible mass compared to the mass of the protons and neutrons. The mass of the electron is about 9.11 × 10^-31 Kg. This makes it the lightest of all the particles listed among the options.
A) 5Ca(OH)₂ + 3H₃PO₄ → Ca₅(PO₄)₃(OH) + 9H₂O
B) m=158 g; w=0.830; m{Ca(OH)₂}=123 g
n(H₃PO₄) = m(H₃PO₄)/M(H₃PO₄) = mw/M(H₃PO₄)
n(H₃PO₄) = 158g*0.830/(98.0g/mol) = 1.3382 mol
n{Ca(OH)₂}=m{Ca(OH)₂}/M{Ca(OH)₂}
n{Ca(OH)₂}=123g/(74.01g/mol)=1.6619 mol
Ca(OH)₂:H₃PO₄ = 5:3
1.6619:1.3382 = 5:4 the limiting reagent is a calcium hydroxide
m{Ca₅(PO₄)₃(OH)} = M{Ca₅(PO₄)₃(OH)}n{Ca(OH)₂}/5
m{Ca₅(PO₄)₃(OH)} = 502.3g/mol*1.6619/5=166.954 g*
*The statement of the problem is incorrect, surplus of a phosphoric acid reacts with a hydroxyapatite. The calculated quantity of a hydroxyapatite is not formed.
3Ca₅(PO₄)₃OH + H₃PO₄ = 5Ca₃(PO₄)₂ + 3H₂O
CaBr2-potassium chloride
Li2O-calcium bromide
No, but. It will seperate into two different layers based on density