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hoa [83]
3 years ago
14

I need help answer with right answer

Chemistry
1 answer:
larisa86 [58]3 years ago
6 0

Answer:

I think it would be D

Explanation:

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A balloon filled with 1.92 g of helium has a volume of 12.5 L. What is the balloon’s volume after 0.850 g of helium has leaked o
Marizza181 [45]

The answer is 1.56L. Avogadro's Law states that the volume of a gas is directly proportional to the number of moles (or a number of particles) of gas when the temperature and pressure are held constant.

V∝n

V₁/n₁m= V₂/n₂

V₁ = initial volume of gas  = 12.5 L

V₂ = final volume of gas = ?

n₁ = initial moles of gas  = 0.016 mole

n₂ = final moles of gas  = 0.016-0.007 = 0.002 mole

V₁/n₁m= V₂/n₂

V₂= 1.56L

Avogadro's Law is in evidence whenever you blow up a balloon. The volume of the balloon increases as you add moles of gas to the balloon by blowing it up.

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Zinc + Hydrochloric Acid → Zinc Chloride and Hydrogen Gas
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Explanation:

because in the right side there is 2 hydrogen( H) and 2 chloride (Cl) to balace them we have to replace 2.

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3 years ago
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Alex built a model to show how light bends when placed into water. To do this, Alex filled a fish tank up with water, and shined
densk [106]

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The model cannot show how light bends.

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What is the volume of 0.640 grams of Oz gas at Standard Temperature and Pressure (STP)?
Ilia_Sergeevich [38]

Answer: The volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

Explanation:

Given: Mass of O_{2} gas = 0.640 g

Pressure = 1.0 atm

Temperature = 273 K

As number of moles is the mass of substance divided by its molar mass.

So, moles of O_{2} (molar mass = 32.0 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.640 g}{32.0 g/mol}\\= 0.02 mol

Now, ideal gas equation is used to calculate the volume as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.0 atm \times V = 0.02 mol \times 0.0821 L atm/mol K \times 273 K\\V = 0.449 L

Thus, we can conclude that the volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

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Which option is an example of physical change?
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