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Elza [17]
3 years ago
5

Is water a solution? If so explain. Im very serious.

Chemistry
2 answers:
aleksandrvk [35]3 years ago
8 0

Answer:

No (If we are talking about pure water)

Explanation:

Water is a compound. Each molecule is made up of only 2 Hydrogen atoms and 1 Oxygen atom.

Dmitrij [34]3 years ago
3 0

Answer:

Is water a solution?

The answer is no.

A solution is a mixture of several substances which is uniform structure throughout a homogeneous neighborhood.

Water is a pure compound substance. It is made by hydrogen and oxygen, but does not carry any property of them. Seriously, water is a pure substance.

Hope this helps!

:)

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Predict the aldol product when the following ketone undergoes self-condensation in the presence of NaOH. Do not show the dehydra
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Answer:

β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal.

Explanation:

When acetaldehyde is treated with dil.NaOH it undergoes self condensation as it contains alpha-hydrogen atom in its compound forming β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal. This compound upon further heating will eliminate a molecule of water forming aldol condensation product namely Crotonaldehyde Or But-2-en-al. see the diagram attached.

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3 years ago
Find out no. of moles present is 72 gm of water?
Alona [7]
72g H2O x 1 mol H2O/18.02g H2O = 3.99 mol H2O 
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3 years ago
How many moles of mercury, Hg, are there in 1.30 x 10^7 atoms of murcury? PLEASE HELP, IT'S URGENT! Thank you! (:
vodka [1.7K]
1 mole Hg ---------------- 6.02x10²³ atoms
??  ------------------------- 1.30 x10⁷ atoms

1.30x10⁷ x 1 / 6.02x10²³ =

= 1.30x10⁷ / 6.02x10²³ => 2.159x10⁻¹⁷ moles

hope this helps!

7 0
3 years ago
Which of the following has the greatest influence on the size and force of waves?
svlad2 [7]
Wind speed bc The faster the wind, the longer it blows, or the farther it can blow uninterrupted, the bigger the waves.
3 0
3 years ago
Read 2 more answers
Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t
Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution = 3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}

l = path length = 2.5 mm = 0.25 cm

I_o = incident light

I = transmitted light

\epsilon = molar absorptivity coefficient = 855dm^3mol^{-1}cm^{-1}

Now put all the given values in the above formula, we get:

\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)

\log \frac{I_o}{I}=0.6947

\frac{I_o}{I}=10^{0.6947}=4.951

If we consider I_o = 100

then, I=\frac{100}{4.951}=20.198

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light I_A = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100

\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%

Therefore, the percentage reduction in intensity is 79.80 %

3 0
4 years ago
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