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3 years ago

5) Determine the mass if lithium hydroxide that is produced when 12.87 g of lithium

Chemistry

1 answer:

netineya [11]3 years ago

4 0

Answer: 26.54 grams

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of lithium nitride}=\frac{12.87g}{34.83g/mol}=0.369moles$

$Li_3N+3H_2O\rightarrow 3LiOH+NH_3$

$Li_3N$ is the limiting reagent as it limits the formation of product and $H_2O$ is the excess reagent

According to stoichiometry :

As 1 moles of $Li_3N$ give = 3 moles of $LiOH$

Thus 0.369 moles of $O_2$ give = $\frac{3}{1}\times 0.369=1.108moles$ of $LiOH$

Mass of $LiOH=moles\times {\text {Molar mass}}=1.108moles\times 23.95g/mol=26.54g$

Thus 26.54 g of $LiOH$ will be produced from the given mass.

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3 years ago

Given 4.80g of ammonium carbonate, find:

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Answer:

1) 0.05 mol.

2) 0.1 mol.

3) 0.05 mol.

4) 0.4 mol.

5) 2.4 x 10²³ molecules.

Explanation:

1) Number of moles of the compound:

no. of moles of ammonium carbonate = mass/molar mass = (4.80 g)/(96.09 g/mol) = 0.05 mol.

2) Number of moles of ammonium ions :

Ammonium carbonate is dissociated according to the balanced equation:

(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.

It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.

∴ The no. of moles of NH₄⁺ ions in 0.05 mol of (NH₄)₂CO₃ = (2.0)(0.05 mol) = 0.1 mol.

3) Number of moles of carbonate ions :

Ammonium carbonate is dissociated according to the balanced equation:

(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.

It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.

∴ The no. of moles of CO₃²⁻ ions in 0.05 mol of (NH₄)₂CO₃ = (1.0)(0.05 mol) = 0.05 mol.

4) Number of moles of hydrogen atoms:

Every 1.0 mol of (NH₄)₂CO₃ contains:

2.0 moles of N atoms, 8.0 moles of H atoms, 1.0 mole of C atoms, and 3.0 moles of O atoms.

∴ The no. of moles of H atoms in 0.05 mol of (NH₄)₂CO₃ = (8.0)(0.05 mol) = 0.4 mol.

5) Number of hydrogen atoms:

It is known that every mole of a molecule or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.

Using cross multiplication:

1.0 mole of H atoms contains → 6.022 x 10²³ atoms.

0.4 mole of H atoms contains → ??? atoms.

∴ The no. of atoms in 0.4 mol of H atoms = (6.022 x 10²³ molecules)(0.4 mole)/(1.0 mole) = 2.4 x 10²³ molecules.

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4 years ago

The highest energy occupied molecular orbital in the f-f bond of the f2 molecule is _____

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The basis of finding the answer to this problem is to know the electronic configuration of Fluorine. That would be: [He] 2s² 2p⁵. The valence electrons, which are the outermost electrons of the atom, are the ones that participate in bonding. Since the highest orbital for F is 2p, that means the highest energy occupied would be 2.

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3 years ago

An ion of oxygen- 16 contains 8 protons and has a 2- charge. How many electrons does it have?

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Answer:

i would say 10, so the anser is A.

Explanation:

because there are the same number of protons and electrons, therefore for a regular O, you are supposed to have only 8 protons, but it is charged, thus, whatever the charge is will be taken into consideration into how much the proton and electron doe it have. Thus, for this case, it has 10, because the charge is negative and you have 8 electron plus 2 = 10.

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3 years ago

Select the correct statement (2.5 points) (A) Elements in the same row are similar in size. (B) Elements in the same column have

Mrrafil [7]

Answer:

Explanation:

We are talking about the periodic table in which elements where put under different rows and columns according to their atomic number (number of protons) in ascendant order.

In rows or periods we can find trends in some properties like atomic radius, electronegativity, etc...). So they are not similar in size. Option A is a false statement.

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3 years ago

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