Answer:
If efficiency is .22 then W = .22 * Q where Q is the heat input
Heat Input Q = 2510 / .22 = 11,400 J
Heat rejected = 11.400 - 2510 = 8900 J of heat wasted
Also, 8900 J / (4.19 J / cal) = 2120 cal
Acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
because the object is slowing down, the acceleration will be negative.
acceleration = (4-34) / 60
acceleration = -30 / 60
acceleration = -0.5 m/s^2
answer : the train is accelerating at -0.5 m/s^2
Answer:
i did not learn this yet im going into 6th grade im still in 5th
i dont know
Given,
The momentum of the object A before the collision, p₁ =80 Ns
The momentum of the object B before the collision, p₂=-30 Ns
Given that the objects stick together after the collision.
From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.
Thus,

Where p is the total momentum of the system at any instant of time.
On substituting the known values,

Therefore the total momentum of the system is 50 Ns
Thus the momentum of the object AB after the collision is 50 Ns
Answer:

Explanation:
Given that,
Mass of an object, m = 3.68 kg
It is whirled in a horizontal circle of radius 881 cm or 8.81 m
The object completes 10.8 revolutions every 18.8
s.
We need to find the centripetal acceleration of the object. It is given by the formula as follows :
...(1)
Where
is angular velocity
10.8 revolutions = 67.85 rad

Put values in equation (1)

So, the centripetal acceleration of the object is
.