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____ [38]
2 years ago
9

The cheetah is considered the fastest running animal in the world. Cheetahs can accelerate to a speed of 21.5 m/s in 2.50 s and

can continue to accelerate to reach a top speed of 28.5 m/s. Assume the acceleration is constant until the top speed is reached and is zero thereafter.
Express the cheetah's top speed in mi/h.
Physics
1 answer:
AleksandrR [38]2 years ago
5 0

Answer: 63.753 mph

Explanation:

28.5 \frac{m}{s} * \frac{1 mile}{1609.34 m} * \frac{3600s}{1 hour} = 63.753 \frac{miles}{hour}

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An automobile engine has an efficiency of 22.0% and produces 2510 J of work. How much heat is rejected by the engine
katrin [286]

Answer:

If efficiency is .22 then  W = .22 * Q   where Q is the heat input

Heat Input    Q = 2510 / .22 = 11,400 J

Heat rejected = 11.400 - 2510 = 8900  J of heat wasted

Also, 8900 J / (4.19 J / cal) = 2120 cal

5 0
3 years ago
A train slows down from 34 m/s to 4 m/s in 60 seconds. what is it's acceleration?
OverLord2011 [107]
Acceleration = change in velocity / time

change in velocity = final velocity - initial velocity

because the object is slowing down, the acceleration will be negative.

acceleration = (4-34) / 60
acceleration = -30 / 60
acceleration = -0.5 m/s^2

answer : the train is accelerating at -0.5 m/s^2
3 0
3 years ago
A power plant running at 31 % efficiency generates 270 MW of electric power. Part A At what rate (in MW) is heat energy exhauste
True [87]

Answer:

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6 0
2 years ago
8. Object A has a momentum of 80 Ns and collides and sticks to object B which has a momentum of -30 Ns. What is the momentum of
BigorU [14]

Given,

The momentum of the object A before the collision, p₁ =80 Ns

The momentum of the object B before the collision, p₂=-30 Ns

Given that the objects stick together after the collision.

From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.

Thus,

p_1+p_2=p

Where p is the total momentum of the system at any instant of time.

On substituting the known values,

\begin{gathered} p=80-30 \\ =50\text{ Ns} \end{gathered}

Therefore the total momentum of the system is 50 Ns

Thus the momentum of the object AB after the collision is 50 Ns

6 0
1 year ago
Question 6 (14 points)
leva [86]

Answer:

a=114\ m/s^2

Explanation:

Given that,

Mass of an object, m = 3.68 kg

It is whirled in a horizontal circle of radius 881 cm or 8.81 m

The object completes 10.8 revolutions every 18.8 s.

We need to find the centripetal acceleration of the object. It is given by the formula as follows :

a=\omega^2 r ...(1)

Where \omega is angular velocity

10.8 revolutions = 67.85 rad

\omega=\dfrac{67.85\ rad}{18.8\ s}\\\\=3.6\ rad/s

Put values in equation (1)

a=3.6^2\times 8.81\\\\a=114\ m/s^2

So, the centripetal acceleration of the object is 114\ m/s^2.

3 0
3 years ago
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